Palindrome Partitioning

Palindrome Partitioning 

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]
参考了这个锅锅的，思路很清晰，用的类似DFS递归实现http://www.sjsjw.com/kf_code/article/033776ABA018056.asp

import java.util.ArrayList;
import java.util.List;

public class Solution {
    
    public List<List<String>> partition(String s) {
        List<List<String>> result = new ArrayList<List<String>>();            //存放结果
        List<String> curList = new ArrayList<String>();                        //记录当前结果
        
        if(s.length() == 0)
            return result;
        getResult(result, curList, s);
        
        return result;
    }
    
    /**
     * 判断字符串是否为回文
     * @param str
     * @return
     */
    public boolean isPalindrom(String str){
        for(int i = 0, j = str.length() - 1; i < j; i++, j--){
            if(str.charAt(i) != str.charAt(j))
                return false;
        }
        
        return true;
    }
    
    /**
     * 递归调用
     * @param curList
     * @param str
     */
    public void getResult(List<List<String>> result,List<String> curList, String str){
        if(str.length() == 0)
            result.add(new ArrayList<String>(curList));                //满足条件添加到结果集中,注意这里因为curList是引用，必须new一个新的list出来
        else{
            for(int i = 1; i <= str.length();i++){
                String head = str.substring(0, i);
                if(isPalindrom(head)){                                //子串是回文
                    curList.add(head);
                    getResult(result, curList, str.substring(i));
                    curList.remove(curList.size() - 1);
                }
            }
        }
    }
//    public void show(List<List<String>> list){
//        for(List<String> list_temp : list){
//            for(String string_temp : list_temp){
//                System.out.print(string_temp + " ");
//            }
//            System.out.println();
//        }
//    }
}