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  • Simplify Path

    Given an absolute path for a file (Unix-style), simplify it.

    For example,
    path = "/home/", => "/home"
    path = "/a/./b/../../c/", => "/c"

    思路

    以/为分界符split,如/a/./b/../../c/,分成a,.,b,..,..,c这样,将a,b..依次入栈,如果,是..出栈,最后从栈底遍历到栈底为最后的路径。因为最后要从栈底遍历到栈顶,我用的是list不是stack

     1 import java.util.ArrayList;
     2 import java.util.List;
     3 
     4 public class Solution {
     5     public String simplifyPath(String path) {
     6         List<String> stack = new ArrayList<String>();            //这里的List有stack的作用
     7         String result = "";
     8         
     9         int ptrOfPath = 1;
    10         String element = "";
    11         while(ptrOfPath < path.length() && path.charAt(ptrOfPath) == '/')
    12             ptrOfPath++;
    13         while(ptrOfPath < path.length() && path.charAt(ptrOfPath) != '/'){
    14             element += path.charAt(ptrOfPath);
    15             ptrOfPath++;
    16         }//while
    17         ptrOfPath ++;
    18         if(!element.equals(".") && !element.equals("..") && !element.equals("/"))
    19             stack.add(element);
    20         element = "";
    21         boolean startNewWord = false;
    22         while(ptrOfPath < path.length()){
    23             if(startNewWord == true)
    24             {
    25                 element = "";
    26                 startNewWord = false;
    27             }
    28             if(path.charAt(ptrOfPath) == '/' || ptrOfPath == path.length() - 1){
    29                 startNewWord = true;
    30                 if(ptrOfPath == path.length() - 1 && path.charAt(ptrOfPath) != '/')
    31                     element += path.charAt(ptrOfPath);
    32                 if(element.length() != 0 && element.equals("..")){
    33                     if(stack.size() != 0)
    34                         stack.remove(stack.size() - 1);                //出栈
    35                 }
    36                 else if(element.length() != 0 && !element.equals(".")){
    37                     stack.add(element);                                //入栈
    38                 }
    39                 ptrOfPath++;
    40                 continue;
    41             }//if
    42             else{
    43                 element += path.charAt(ptrOfPath ++);
    44             }
    45         }//while
    46         if(stack.size() == 0)
    47             return "/";
    48         //遍历list获取结果
    49         for(String str : stack){
    50             result += "/";
    51             result += str;
    52         }//for
    53         
    54         return result;
    55     }
    56 }
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  • 原文地址:https://www.cnblogs.com/luckygxf/p/4218972.html
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