Combination Sum II

Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.

Each number in C may only be used once in the combination.

Note:

• All numbers (including target) will be positive integers.
• Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
• The solution set must not contain duplicate combinations.

For example, given candidate set 10,1,2,7,6,1,5 and target 8, 
A solution set is: 
[1, 7] 
[1, 2, 5] 
[2, 6] 
[1, 1, 6] 

这道题只需在Combination Sum稍微改一下就行了

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import org.w3c.dom.CDATASection;

public class Solution {
    public List<List<Integer>> combinationSum2(int[] num, int target) {
        Arrays.sort(num);
        List<List<Integer>> result = new ArrayList<List<Integer>>();
        getResult(result, new ArrayList<Integer>(), num, target, 0);
        
        return result;
    }
    
    private void getResult(List<List<Integer>> result, List<Integer> cur, int candidates[], int target, int start){
        if(target > 0){
            for(int i = start; i < candidates.length && target >= candidates[i]; i++){
                cur.add(candidates[i]);
                getResult(result, cur, candidates, target - candidates[i], i + 1);
                cur.remove(cur.size() - 1);
                
            }//for
        }//if
        else if(target == 0 && !result.contains(cur)){            
            result.add(new ArrayList<Integer>(cur));
            
        }//else if
    }
    
}