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  • JSON入门之二:org.json的基本用法 分类: C_OHTERS 2014-05-14 11:25 6001人阅读 评论(0) 收藏


    java中用于解释json的主流工具有org.json、json-lib与gson,本文介绍org.json的应用。

    官方文档:

    http://www.json.org/java/

    http://developer.android.com/reference/org/json/package-summary.html

    1、主要类

    Classes


    JSONArray

    A dense indexed sequence of values. 

    JSONObject

    A modifiable set of name/value mappings. 

    JSONStringer

    Implements toString() and toString()

    JSONTokener

    Parses a JSON (RFC 4627) encoded string into the corresponding object. 

    Exceptions


    JSONException

    Thrown to indicate a problem with the JSON API. 

    2、构建一个JSON文本的方法

    (1)使用JSONObject的构造方法,然后toString。

    创建一个JSONObject对象后,再使用put(String, Object)方法添加键值对。

    toString()方法将JSONObject对象按照JSON的标准格式进行封装。

    (2)使用JSONStringer创建JSON文本。

    String myString = new JSONStringer().object()   
    .key("name")  
    .value("小猪")   
    .endObject()  
    .toString();
    完整程序如下:

    package com.ljh.jsondemo;
    
    import org.json.JSONException;
    import org.json.JSONObject;
    import org.json.JSONStringer;
    import org.junit.Test;
    
    public class JSONObjectTest {
    
    	@Test
    	public void test() {
    		System.out.println(prepareJSONObject());
    		System.out.println(prepareJSONObject2());
    	}
    	
    	private static String prepareJSONObject(){
    		JSONObject studentJSONObject = new JSONObject();
    		try {
    			studentJSONObject.put("name", "Jason");
    			studentJSONObject.put("id", 20130001);
    			studentJSONObject.put("phone", "13579246810");
    		} catch (JSONException e) {
    			e.printStackTrace();
    		}
    		
    		return studentJSONObject.toString();
    	}
    	
    	private static String prepareJSONObject2(){
    		JSONStringer jsonStringer = new JSONStringer();
    		try {
    			jsonStringer.object();
    			jsonStringer.key("name");
    			jsonStringer.value("Jason");
    			jsonStringer.key("id");
    			jsonStringer.value(20130001);
    			jsonStringer.key("phone");
    			jsonStringer.value("13579246810");
    			jsonStringer.endObject();
    		} catch (JSONException e) {
    			e.printStackTrace();
    		}
    		return jsonStringer.toString();
    	}
    
    }
    
    输出结果如下:

    {"id":20130001,"phone":"13579246810","name":"Jason"}
    {"name":"Jason","id":20130001,"phone":"13579246810"}

    结论:

    (1)使用JSONObject构造的JSON文本顺序杂乱,使用JSONStringer则按顺序排列。

    (2)关于二者之间的比较,android官方文档认为:

     Most application developers should use those methods directly and disregard this API. For example:

     JSONObject object = ...
     String json = object.toString();

    Stringers only encode well-formed JSON strings. In particular:

    • The stringer must have exactly one top-level array or object.
    • Lexical scopes must be balanced: every call to array() must have a matching call to endArray() and every call to object() must have a matching call to endObject().
    • Arrays may not contain keys (property names).
    • Objects must alternate keys (property names) and values.
    • Values are inserted with either literal value calls, or by nesting arrays or objects.
    Calls that would result in a malformed JSON string will fail with a JSONException.

    This class provides no facility for pretty-printing (ie. indenting) output. To encode indented output, use toString(int) or toString(int).

    Some implementations of the API support at most 20 levels of nesting. Attempts to create more than 20 levels of nesting may fail with a JSONException.

    Each stringer may be used to encode a single top level value. Instances of this class are not thread safe. Although this class is nonfinal, it was not designed for inheritance and should not be subclassed. In particular, self-use by overrideable methods is not specified. See Effective Java Item 17, "Design and Document or inheritance or else prohibit it" for further information.

    即:

    一般情况下使用JSONObject即可,但对于一些嵌套的JSON,某些JSONArray没有key,只有value等特殊情况,则使用JSONStringer.


    3、读取JSON文本内容。

    使用JSONTokener类的相关方法。

    package com.ljh.jsondemo;
    
    import org.json.JSONException;
    import org.json.JSONObject;
    import org.json.JSONTokener;
    import org.junit.Test;
    
    public class JSONTokenerTEst {
    
    	@Test
    	public void test() {
    		System.out.println(getJSONContent());
    	}
    	
    	private static String JSONText = "{"id":20130001,"phone":"13579246810","name":"Jason"}";
    	
    	private static String getJSONContent(){
    		JSONTokener jsonTokener = new JSONTokener(JSONText); 
    		JSONObject studentJSONObject;
    		String name = null;
    		int id = 0;
    		String phone = null;
    		try {
    			studentJSONObject = (JSONObject) jsonTokener.nextValue();
    			name = studentJSONObject.getString("name");
    			id = studentJSONObject.getInt("id");
    			phone = studentJSONObject.getString("phone");
    			
    		} catch (JSONException e) {
    			e.printStackTrace();
    		}
    		return name + "  " + id + "   " + phone;
    	}
    }
    
    输出结果如下:

    Jason  20130001   13579246810

    事实上,使用JSONObject的构造方法也可直接创建JSONObject对象。

    private static String getJSONContent2(){
    	String name = null;
    	int id = 0;
    	String phone = null;
    	try {
    		JSONObject studentJSONObject = new JSONObject(JSONText); 
    		name = studentJSONObject.getString("name");
    		id = studentJSONObject.getInt("id");
    		phone = studentJSONObject.getString("phone");
    		
    	} catch (JSONException e) {
    		e.printStackTrace();
    	}
    	return name + "  " + id + "   " + phone;
    }

    总结:单纯使用JSONObject可以解决大部分的JSON处理问题。




    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/lujinhong2/p/4637341.html
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