div2 620 A

A

Tag

数学，思维

---

设所需要的时间为 (t),两只兔子之间的距离为 (c ur)

(cut = (y-bt) - (x+at))

(t = (y-x)/(a+b))

#include <bits/stdc++.h>
using namespace std;
int main() {
    int x,y,t,a,b,ans;
    cin >> t;
    while(t --) {
        cin >> x >> y >> a >> b;
        if((y - x) % (a + b) == 0) cout << (y - x) / (a + b) << endl;
        else cout << "-1
";
    }
    return 0;
}