POJ 1979
BFS 连通块
输入的(n) 和(m) 是反的要注意
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
using namespace std;
#define endl '
'
const int N = 200;
char g[N][N];
int n,m,ans,sx,sy;
int dx[4] = {0,0,1,-1};
int dy[4] = {1,-1,0,0};
bool st[N][N];
struct node {
int x,y;
};
void bfs(int x,int y) {
queue<node> q;
q.push({x,y});
st[x][y] = 1;
while(q.size()) {
node t = q.front();
q.pop();
for(int i = 0;i < 8; ++i) {
int nx = t.x + dx[i],ny = t.y + dy[i];
if(nx >= 0 && nx < n && ny >= 0 && ny < m && g[nx][ny] == '.' && !st[nx][ny]) {
q.push({nx,ny});
st[nx][ny] = 1;
ans ++;
}
}
}
}
int main() {
ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
while(cin >> m >> n && n && m) {
memset(st,0,sizeof st);
ans = 1;
for(int i = 0;i < n; ++i)
for(int j = 0;j < m; ++j) {
cin >> g[i][j];
if(g[i][j] == '@') sx = i,sy = j;
}
bfs(sx,sy);
cout << ans << endl;
}
return 0;
}