Add Odd or Subtract Even
time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
You are given two positive integers a and b.
In one move, you can change a in the following way:
Choose any positive odd integer x (x>0) and replace a with a+x;
choose any positive even integer y (y>0) and replace a with a−y.
You can perform as many such operations as you want. You can choose the same numbers x and y in different moves.
Your task is to find the minimum number of moves required to obtain b from a. It is guaranteed that you can always obtain b from a.
You have to answer t independent test cases.
Input
The first line of the input contains one integer t (1≤t≤104) — the number of test cases.
Then t test cases follow. Each test case is given as two space-separated integers a and b (1≤a,b≤109).
Output
For each test case, print the answer — the minimum number of moves required to obtain b from a if you can perform any number of moves described in the problem statement. It is guaranteed that you can always obtain b from a.
Example
input
5
2 3
10 10
2 4
7 4
9 3
output
1
0
2
2
1
Note
In the first test case, you can just add 1.
In the second test case, you don’t need to do anything.
In the third test case, you can add 1 two times.
In the fourth test case, you can subtract 4 and add 1.
In the fifth test case, you can just subtract 6.
分差的奇偶性，和大小
#include <bits/stdc++.h>
using namespace std;
int main()
{
int t;
cin >> t;
while (t--)
{
int a,b,c;
cin>>a>>b;
if(a==b) cout<<0<<endl;
else if(a>b)
{
if((a-b)%2==0)cout<<1<<endl;
else cout<<2<<endl;
}
else {
if((b-a)%2==0)cout<<2<<endl;
else cout<<1<<endl;
}
}
}