同样的代码在java和c++中结果不同

#include <iostream>
using namespace std;
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
class A {
    public:
        void m() {
            n();
        }

    public:
        virtual void n() {
            cout<<"调用了父类的n函数";
        }

};

class B:public A {

    public:
        void m() {
            A::m();
        }

    public:
        void n() {
            cout<<"调用了子类的n函数";
        }

};
int main(int argc, char** argv) {
    B b;
    b.m();
    return 0;
}

class A
{
public void m()
{
	n();
}
public void n()
{
System.out.println("调用了父类的n函数");	
}
}

class B extends A
{

public void m()
{
	super.m();
}

public void n()
{
System.out.println("调用了子类的n函数");	
}
}

public class main {
	public static void main(String[] args) {
		// TODO Auto-generated method stub
    B b=new B();
    b.m();
	}
}

c++输出父类，java输出子类。　　

 原因java默认多态，动态绑定。c++需要加virtual,加上后均为子类