--测试环境,20远端,30本地;
--准备1,20远端建立表的同义词,用户信息;
1.11
---------------------------------------------------准备阶段,有表有用户可以忽略此步骤-------------------------------------------------------------------
SQL> conn yang/y ERROR: ORA-01017: invalid username/password; logon denied --无效的用户名密码,拒绝进入系统
Warning: You are no longer connected to ORACLE.警告:你是不能尝试连接到oracle
SQL> desc dba_users; ----查询视图
SQL> select USERNAME,USER_ID,ACCOUNT_STATUS,LOCK_DATE,DEFAULT_TABLESPACE from dba_users where username='YANG';
no rows selected --没有记录
SQL> create user yang identified by y; --创建用户,授予两个角色
SQL> grant connect,resource to yang;
create table abcdefaefef as select * from hr.employees --创建表,无法查询到-表存在,权限不足导致
*
ERROR at line 1:
ORA-00942: table or view does not exist
SQL> grant select any table to yang;----授予权限后,角色权限需要在新的用户会话生效(oracle的一致性:你不能说我正查着dba的视图,回收权限后,我报错,返回权限不足吧)
SQL> create table abcdefaefef as select * from hr.employees; --创建测试表
SQL> select USERNAME,USER_ID,ACCOUNT_STATUS,LOCK_DATE,DEFAULT_TABLESPACE from dba_users where username='YANG';---查询用户信息
YANG 107 OPEN USERS
---------------------------------------------------------------------------------------表、用户准备完毕------------------
1.12:
创建私有同义词(自己看到 ):
create synonym a for abcdefaefef
*
ERROR at line 1:
ORA-01031: insufficient privileges
--需要权限:SQL> grant create any synonym to yang; =========(操作)==========
SQL> create synonym a for abcdefaefef; ==============(操作)=================
SQL> select count(*) from a; ---当前用户可以使用查询;
select * from yang.a ----SYS用户也可以查询,虽然这个同义词是私有的;
SQL> select count(*) from yang.abcdefaefef; --HR用户无法查询表,同义词更无法识别;
授予权限,让Hr能查询表,验证能否可以使用同义词查询;
SQL> grant select on yang.abcdefaefef to hr;
SQL> select count(*) from yang.abcdefaefef;
COUNT(*) ---------- 107
SQL> select count(*) from yang.a;
COUNT(*) ---------- 107
---同义词,私有情况下,收到的访问约束局限在于表,而不再与同义词本身;
1.13
---创建公共的同义词
1)yang用户创建:
create public synonym b for abcdefaefef
*
ERROR at line 1:
ORA-01031: insufficient privileges
SQL> grant create public synonym to yang;
SQL> create public synonym b for abcdefaefef;----创建公共的同义词需要的权限不同;一个表的同义词可以有多个;
2)我们回收用户创建私有同义词的权限,公有的不回收,创建私有同义词,验证:
public synonym 权限能否创建私有同义词:
SQL> revoke create any synonym from yang;
SQL> select * from session_privs; ---验证回收的权限------发现次权限会话生效,回收也是;
drop synonym a; ---删除同义词;
create synonym a for abcdefaefef;
ERROR at line 1:
ORA-01031: insufficient privileges ----这个权限有点意思,公有的权限无法创建私有的同义词;
-----------------反过来呢?
revoke create public synonym from yang;
SQL> grant create any synonym to yang;
SQL> select * from session_privs;
create public synonym a for abcdefaefef;
ERROR at line 1:
ORA-01031: insufficient privileges
3) 创建公共同义词a;
然后对比,查询能查询数据的用户对象;
SQL> grant create public synonym to yang;
SQL> create public synonym a for abcdefaefef;
---排除创建本身的用户
--使用SYS用户查询:
SQL> select count(*) from a;
COUNT(*) ---------- 87024
SQL> desc a; ----------------------------发现如果有其它同义词相同,会造成干扰
--测试HR:用户查询公共同义词
select * from a;----------------------OK,可以查询到数据
SQL> create table a(id int); ---创建同义词的表名,干扰
Table created.
SQL> select * from a; -----查询的是本用户下的表名;
no rows selected------------------------------发现如果用户下的表名与公共同义词一样,也会造成干扰
--测试HR,没有访问yang.ABCDEFAEFEF表权限的时候;
SQL> revoke select on yang.ABCDEFAEFEF from hr;
select count(*) from yang.ABCDEFAEFEF
*
ERROR at line 1:
ORA-00942: table or view does not exist
SQL> drop table a;
select count(*) from a
*
ERROR at line 1:
ORA-00942: table or view does not exist---------没有访问表的权限,同义词公共也看不到
SQL> grant select on yang.ABCDEFAEFEF to hr;
SQL> create table a(id int);
select * from yang.ABCDEFAEFEF
SQL> select * from yang.a;
select * from yang.a
*
ERROR at line 1:
ORA-00942: table or view does not exist----
---小结:公共同义词,一样收到表是否能被访问的风险;
--同义词无法username.object指定,无法指定用户+对象;
--同义词收到表名、同义词朋友的干扰,建议名称奇怪一点好;
--建议查询同义词之前先desc 看一下结构是否相同;
--查询同义词:
ORA-01031: insufficient privileges --公共同义词也需要权限才能删除(grant drop public synonym to yang);
SQL> drop public synonym b;
SQL> select * from dba_synonyms where table_name='ABCDEFAEFEF';
PUBLIC A YANG ABCDEFAEFEF
YANG B YANG ABCDEFAEFEF
-------------------------------------------------------------------------------------------------------------------
以上同义词准备完毕:共有同义词a, 私有同义词b=》用户yang;
以下开始准备dblink配置
----------------------------------------------------------------------------------------------------------------
--创建dblink测试:
dblink,是啥其实就是个连接串,连接到你想查询的数据库上;
创建是在自己本地上创建:
30本地,abc用户,想查询20ip,下的yang用户下的表;
SQL> select * from session_privs;
SQL> select * from user_sys_privs where privilege like upper('%DATABASE LINK%'); ----查询数据库的dblink
no rows selected
create /* public */ database link dblink1 connect to yang identified by y using '(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=192.168.54.20)(PORT=1521)))(CONNECT_DATA=(SERVICE_NAME=jx)))';
---创建完毕:测试:
select * from ab@dblink1
*
ERROR at line 1:
ORA-12541: TNS:no listener -----发现都找不着TNS服务了
grid$ cd /picclife/app/11.2.0/grid/network/admin/ ---先搞自己的监听,tns配置
listener.ora tnsnames.ora
oracle$ sqlplus hr/hr@192.168.54.30:1521/bj
LISTENER =
(DESCRIPTION_LIST =
(DESCRIPTION =
(ADDRESS = (PROTOCOL = IPC)(KEY = EXTPROC1521))
(ADDRESS = (PROTOCOL = TCP)(HOST = localhost)(PORT = 1521))
)
)
Instance "bj", status READY, has 1 handler(s) for this service...
时刻准备着为实例xx服务
The command completed successfully --这个命令是顺利成功的;
grid/network/admin$ cat tnsnames.ora
yang2 =
(DESCRIPTION=
(ADDRESS_LIST =
(ADDRESS = (PROTOCOL = TCP)(HOST = 192.168.54.30)(PORT = 1521))
)
(CONNECT_DATA=
(SERVICE_NAME = bj)
)
)
$ sqlplus hr/hr@yang2 ==============================以上是本地的监听+tns配置
select * from ab@dblink1-----再次查询:报错不一样了;
*
ERROR at line 1:
ORA-02019: connection description for remote database not found
连接为遥远的数据库,连接未找到;
+++++
继续配置,本地的tnsnames,ora文件,存放加入,远程的tns配置文件;(有自己的,但是没有远程的tns配置文件,发不出去)
===在本地: tnsnames.ora文件中加入,远程,远端的tnsnames.ora配置文件信息,保存退出;
--查询验证: sqlplus sys/oracle@yang1 as sysdba
SQL> select instance_name from v$Instance;---查询数据库实例
INSTANCE_NAME ---------------- jx
SQL> host echo $ORACLE_SID +ASM1 --查询本地的sid,实例啥
---本地环境是,使用ASM存储的单节点,因此,tnsname,listener都是grid用户管理的;
---代表什么:可以通过tnsnames.ora文件,去访问其他数据库,登陆其它数据库;
select * from ab@dblink1 ==SYS用户,可以使用,abc用户却不能使用
58 rows selected.
SQL> select owner,object_name from dba_objects where object_type='DATABASE LINK';
OWNER -------------------------------------------OBJECT_NAME ----------------------------------
SYS DBLINK1 ---发现搞错了
PUBLIC QQQ -
---------------------------------------------------------------DBLINK创建了一个私有,其它人不能用---------再加个公有的呗
grant create public database link to abc; --授予创建public dblink权限
conn abc/abc;
create public database link yuan1 connect to yang identified by y using '(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=192.168.54.20)(PORT=1521)))(CONNECT_DATA=(SERVICE_NAME=jx)))';
select * from ab@yuan1 ====OK---查询验证OK
SQL> select * from user_sys_privs where privilege like upper('%DATABASE LINK%');----查询当前用户对DBLINK的权限
USERNAME用户拥有着 ----------- PRIVILEGE权限查询 ---------------- ADMIN是否能联级授予(能否给人钱,有决定权)
ABC CREATE PUBLIC DATABASE LINK NO
SQL> select * from cat@yuan1;
TABLE_NAME --------------------------- TABLE_TYPE -----------------
AB TABLE
ABCDE TABLE
ABCDEFAEFEF TABLE
---回到最初: 表太长,建立了同义词,本地还能使用远程的公共同义词进行查询吗?
select * from a@yuan1; ==public 可以查询
select * from b@yuan1; ====私有也可以,证明:远端远程一样可以只有能看表,就能通过同义词查询
======================================================================================
dblink如何查询:
select owner,object_name from dba_objects where object_type='DATABASE LINK';
SYS DBLINK1
PUBLIC QQQ
PUBLIC YUAN1
select * from dba_db_links;---可以查询完整的DBLINK 信息
PUBLIC YUAN1 YANG (DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=192.168.54.20)(PORT=1521)))(CONNEC 19-OCT-17
T_DATA=(SERVICE_NAME=jx)))
dblink如何删除:
drop dblink qqq;
select * from dba_db_links where db_link='QQQ';
YANG
ORA-01031: insufficient privileges ---公共的DBLINK,即使是拥有着也没有权限删除
SQL> show user USER is "YANG" SQL> conn / as sysdba Connected.
SQL> drop public database link qqq; =========公共的DBLINK,使用SYS用户删除
grant create database link to abc;
create database link si1 connect to yang identified by y using '(DESCRIPTION=(ADDRESS_LIST=(ADDRESS=(PROTOCOL=TCP)(HOST=192.168.54.20)(PORT=1521)))(CONNECT_DATA=(SERVICE_NAME=jx)))';
drop database link si1; ===================私有的DBLINK,自己的用户可以删除
drop database link abc.si1 ========================SYS找不到私有的DBLINK,藏起来了
*
ERROR at line 1:
ORA-02024: database link not found===咋整;
大神有方法,此处抄袭:http://blog.itpub.net/29337971/viewspace-1129917/ --我没成功,先留着以后在学
SQL> select owner||'.'||db_link from dba_db_links where db_link not like '%OGG%';
OWNER||'.'||DB_LINK -------------------------------------------------------------------------------- SYS.DBLINK1
PUBLIC.YUAN1
ABC.SI1
小结:共有,私有的DBLINK与同义词一样,创建的权限分开的;
其次:删除共有的dblink,sys用户,私有 谁创建的,谁删除;SYS找不着对象
删除DBLINK:能否禁用呢?
数据库级别禁止功能:
SQL> alter system set open_links=0 scope=spfile;
ORA-02020: too many database links in use==数据库使用过多的DBLINK
SQL> alter system set open_links=4 scope=spfile;
SQL> startup force;
---如何禁止单个呢?
dba_db_links
select * from dba_db_links;
SQL> select count(*) from cat@yuan1;
COUNT(*) ---------- 6
没实现成功!!!!!!!!!!!!!!!!!!
alter
session
close
database
link
'dblink_name'
---------------------------------------------片外----------------------------------------------------
同义词--删除同义词依托的对象后,同义词是什么状态:
select object_name,object_type,status from user_objects where object_name='YANG' or object_name='ABCDEFAEFEF';
ABCDEFAEFEF TABLE VALID
drop table ABCDEFAEFEF ;
select * from dba_synonyms where table_name='ABCDEFAEFEF';
select * from a;
ORA-00980: synonym translation is no longer valid 同义词长时间不是有效的
对象、私有同义词、公共同义词是否可以存在三者同名的情况?
对象与公司同义词相等,对象优先级最高;
共有私有同义词一样:
SQL> create table abcdefaefef as select * from hr.employees; ===公私同义词不一样,冲突,提升名称已被使用;
SQL> create synonym a for abcdefaefef;
create public synonym a for yang.abcdefaefef
*
ERROR at line 1:
ORA-00955: name is already used by an existing object