原文:https://blog.csdn.net/ren814/article/details/81742242
<resultMap id="menuModelMap" type="com.yyzq.springboot.model.MenuModel" > <id column="id" property="id" jdbcType="BIGINT" /> <result column="menuname" property="menuname" jdbcType="VARCHAR" /> <result column="sort" property="sort" jdbcType="TINYINT" /> <result column="inputtime" property="inputtime" jdbcType="TIMESTAMP" /> <collection property="models" ofType="com.yyzq.springboot.model.Model"> <id column="model_id" property="id" jdbcType="BIGINT" /> <result column="modelname" property="modelname" jdbcType="VARCHAR" /> <result column="model_sort" property="sort" jdbcType="TINYINT" /> <result column="model_inputtime" property="inputtime" jdbcType="TIMESTAMP" /> <result column="url" property="url" jdbcType="VARCHAR" /> </collection> </resultMap>
<select id="selectMenuModel" parameterType="Integer" resultMap="menuModelMap"> SELECT m.id , m.menuname, m.sort, m.inputtime, d.id AS model_id, d.modelname , d.sort AS model_sort, d.url,d.inputtime AS model_inputtime FROM `es_menu_model` mm LEFT JOIN `es_menu` m ON m.id = mm.es_menu_id LEFT JOIN `es_model` d ON d.id = mm.es_model_id WHERE mm.`es_menu_id` = #{id} </select>
以上为正确。
错误区:在结果集中,将俩个column中的ID混淆,我这边是区分的id和model_id,如果俩个都为同样的字段,系统在数据筛选的时候会出现无法判断,所以只能读取第一条数据作为最后结果。切记,结果集有集合的,在mapper文件写column的时候不设为一样的,在具体的sql中修改列名字
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原文链接:https://blog.csdn.net/ren814/article/details/81742242