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  • if_else 语句出现 warning C4715: “FunCompare”: 不是所有的控件路径都返回值

    定义一个比较的函数compare,出现问题warning C4715: “FunCompare”: 不是所有的控件路径都返回值

     1 int  FunCompare(const Fraction &f1,const Fraction &f2)
     2 {
     3     double number1,number2;
     4     number1=f1.GetNum()/f1.GetDenom();
     5     number2=f2.GetNum()/f2.GetDenom();
     6     if (number1 == number2)
     7     {return 0;}
     8     else if (number1 >number2)
     9     {return 1;}
    10     else if (number1 <number2)
    11     {return -1;}
    12 }

    然后,添加return 0后,改正上述warning出现的错误,但是结果总是只返回number1 == number2:

    int  FunCompare(const Fraction &f1,const Fraction &f2)
    {
        double number1,number2;
        number1=f1.GetNum()/f1.GetDenom();
        number2=f2.GetNum()/f2.GetDenom();
        if (number1 == number2)
        {return 0;}
        else if (number1 >number2)
        {return 1;}
        else if (number1 <number2)
        {return -1;}
        return 0;
    }

    然后再改正,修改warning的错误,但是还是不能正确得到结果,较上边的改正方法,这个改正方法更加好点:

    int  FunCompare(const Fraction &f1,const Fraction &f2)
    {
        double number1,number2;
        number1=f1.GetNum()/f1.GetDenom();
        number2=f2.GetNum()/f2.GetDenom();
        if (number1 == number2)
        return 0;
        else if (number1 >number2)
        return 1;
        else 
        return -1;
    }

    最后一次改正:

    int  FunCompare(const Fraction &f1,const Fraction &f2)
    {
        double number1,number2;
        number1=1.0*f1.GetNum()/f1.GetDenom();
        number2=1.0*f2.GetNum()/f2.GetDenom();
        if (number1 == number2)
        return 0;
        else if (number1 >number2)
        return 1;
        else 
        return -1;
    }
    因为你不加1.0*的话,你的两个操作数是整数做除法,结果就是整数,如果乘以1.0的话,结果就是浮点数,你可以打印一下num1,num2看看加与不加*1.0的结果的。
    int  FunCompare(const Fraction &f1,const Fraction &f2)
    {
        double number1,number2;
        number1=1.0*f1.GetNum()/f1.GetDenom();
        number2=1.0*f2.GetNum()/f2.GetDenom();
        if (number1 == number2)
        return 0;
        else if (number1 >number2)
        return 1;
        else 
        return -1;
    }
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  • 原文地址:https://www.cnblogs.com/lwflourish/p/4103143.html
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