Solved:2
rank:452
I. Werewolf
没有铁人 找铁狼 如果一个环中只有一条狼人边那个人就是铁狼
说铁狼是好人的人也是铁狼
#include <bits/stdc++.h> using namespace std; int tmp, ans, lang; char s[25]; struct node { int to, nex, ty; }E[200005]; int head[100005]; int col[100005]; int l[100005]; int r[100005]; void dfs(int x, int fa) { col[x] = tmp; int c = head[x]; for(int i = c; i; i = E[i].nex) { int v = E[i].to; if(v == fa) continue; if(col[v]) continue; dfs(v, x); } } void dfs1(int x, int fa) { ans++; int c = head[x]; for(int i = c; i; i = E[i].nex) { int v = E[i].to; if(v == fa) continue; if(E[i].ty) dfs1(v, x); } } int main() { int T; scanf("%d", &T); while(T--) { int cnt = 0; lang = tmp = ans = 0; int n; scanf("%d", &n); memset(head, 0, sizeof(int) * (n + 2)); memset(col, 0, sizeof(int) * (n + 2)); for(int i = 1; i <= n; i++) { int x; scanf("%d%s", &x, s); if(s[0] == 'v') { E[++cnt].to = x; E[cnt].nex = head[i]; E[cnt].ty = 0; head[i] = cnt; E[++cnt].to = i; E[cnt].nex = head[x]; E[cnt].ty = 1; head[x] = cnt; } else { lang++; l[lang] = i; r[lang] = x; } } for(int i = 1; i <= n; i++) { if(col[i]) continue; tmp++; dfs(i, 0); } for(int i = 1; i <= lang; i++) if(col[l[i]] == col[r[i]]) dfs1(r[i], 0); printf("0 %d ", ans); } return 0; }