poj水题ID3030

Problem：

Input

The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, r, e and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: −10⁶ ≤ r, e ≤ 10⁶ and 0 ≤ c ≤ 10⁶.

Output

Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference.

Sample Input

3
0 100 70
100 130 30
-100 -70 40

Sample Output

advertise
does not matter
do not advertise

我的submission：（又是一次性通过哦，很水的题啦，连我这样的菜鸟都可以通过，O(∩_∩)O哈哈~）

#include <iostream>
using namespace std;
int main()
{
     int i,r,e,c;
     cin>>i;
     while(i>0)
     {
         cin>>r>>e>>c;
              if(e-c>r) cout<<"advertise"<<endl;
              else if (e-c==r)cout<<"does not matter"<<endl;
              else cout<<"do not advertise"<<endl;
              i--;                              
         
               }
     return 0;
 }

　　PS：input中描述的蓝色加粗部分，其实是输入值的限定条件，起初整错了陷入死循环了；其实ACM这个平台对题目的验证，貌似对这样的限定条件并无要求，也就是说不会用非法值去验证你的程序是否通过。这也是做ACM的一个小经验吧，嘿嘿