大端模式，指针数组

#include <stdio.h>

int main (void) {
      arrayPointer();
    int arr[3] = {11,3,4};
    int *p1;
    char *p2=(char*)arr;
    int i;
      int size1=sizeof(arr)/sizeof(arr[0]);
      int size2=(int)sizeof(arr);
    p1 = arr;
    printf("*p1=%d,size1=%d\n", *p1,size1);
    printf("*p2=%d,size2=%d\n", *p2,size2);
      endian();
    for(i = 0; i < size1; i++) {
        printf("%d\n", *p1);
        p1++;
    }
   for(i = 0; i < size2; i++) {
        printf("%d\n", *p2);
        p2++;
    }
    return 0;
}
/*
function for testing the big or little model
*/
void endian(void) 
{ 
        int i = 1; 
 
        if (*(char *) &i == 1) 
                printf("Little endian \n"); 
        else 
                printf("Big endian \n"); 
 
        return; 
} 
/*
test for array of pointer
*/
void arrayPointer()
{
char a[]="hi"; 
char b[]="hello"; 
char *name[]={a,b}; 
*name="bye"; 
puts(a); 
}

大端模式判断， 

　　

在线测试：http://codepad.org/G2JRgDXE