zoukankan      html  css  js  c++  java
  • django 分页

    view.py

    # 分页
    def paging(request):
        # 丛数据库表取出来的数据总数
        count_data = len(message.objects.all())
        # 当前页数,因为url的传值是字符串,所以需要转成整形
        page = int(request.GET.get("page"))
        # 每页显示3条数据
        per_page_count = 3
        # 开始的索引
        start_dat = (page - 1) * per_page_count
        # 结束的索引
        end_data = page * per_page_count
        # 数据切片
        data = message.objects.all()[start_dat:end_data]
        # 上一页
        prev_pager = page - 1
        # 下一页
        next_pager = page + 1
    
        return render(request,"paging.html",{"list":data,"prev_pager":prev_pager,"next_pager":next_pager})
    

      

    html

    <!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>分页</title>
    </head>
    <body>
      <h1>信息展示</h1>
        <table>
        <tr>
            <th>用户名</th>
            <th>密码</th>
        </tr>
        {% for line in list %}
        <tr>
            <td>{{line.username}}</td>
            <td>{{line.password}}</td>
        </tr>
        {% endfor %}
        </table>
        <a href="{% url "paging" %}?page={{ prev_pager }}">上一页</a>
        <a href="{% url "paging" %}?page={{ next_pager }}">下一页</a>
    </body>
    </html>
    

      

    urls.py

     url(r'^paging.html$', views.paging,name='paging'),
  • 相关阅读:
    课堂测试-单元测试(比较大小)
    第三周进度条
    软件工程个人作业02
    构建之法——阅读笔记02
    第二周学习进度条
    第一周学习进度条
    软件工程个人作业01
    构建之法阅读笔记01
    java课堂测试
    Java验证码程序
  • 原文地址:https://www.cnblogs.com/lystbc/p/9357397.html
Copyright © 2011-2022 走看看