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  • Codeforces Hello2015第一题Cursed Query

    英文题面:

    De Prezer loves movies and series. He has watched the Troy for like 100 times and also he is a big fan of Supernatural series.So, he did some researches and found a cursed object which had n lights on it and initially all of them were turned off.Because of his love to the Troy, he called that object Troy.

    He looked and saw a note on it in Khikulish (language of people of Khikuland): "Ma in hame rah umadim, hala migi ... ? ... Mage man De Prezer am k mikhay mano ... ? .... Man se sale ... To boro .... beshur manam miram ... o mishuram".

    He doesn't know Khikulish, so just ignored the note and tested the Troy.

    He realized that the light number i stays turned on for exactly ai seconds, and then it turns itself off (if it is turned on, in time t, in time t + ai - 1 it will be turned on, but on time t + ai it won't be) and the next light will be turned on (if i < n, next light is the light number i + 1, otherwise it is light with number 1).

    For example if n = 2 and we turn on the first light in time 0, it will be turned on in hole interval [0, a1) and in hole interval [a1, a1 + a2) the second light will be turned on and so on.

    In time 0 he turns on the light number 1.

    De Prezer also loves query.So he gives you q queries.In each query he will give you integer t (the time a revengeful ghost attacked him) and you should print the number of the light that is turned on, in time t.

    Input

    The first line of input contains two integers n and q.

    The second line contains n space separated integers, a1, a2, ..., an .

    The next q lines, each line contains a single integer t .

    1 ≤ n, q ≤ 105

    1 ≤ ai ≤ 109

    1 ≤ t ≤ 1018

    Output

    For each query, print the answer in one line.

     

            就是说有n盏灯,然后给出每盏灯亮的时间(第一盏从时刻0開始亮直到时刻0+a1-1,第二盏在a1时刻亮起,以此类推),然后题目给出q组询问,询问内容是一个t,要你给出t时刻亮的时哪盏灯。

    我的做法是每次询问就来一次二分查找,log2n的复杂度再盛上10^5次询问能够接受。

    Sample test(s):

    Input
    5 7
    1 2 3 4 5
    1
    2
    3
    7
    14
    15
    16
    Output
    2
    2
    3
    4
    5
    1
    2

            这组測试数据还是业界良心的。爆出了可能出错的坑,这一串灯是循环的首尾相接地亮。所以那个t是10^18这么大,要取模。

     

    代码:

     

    #include <iostream>
    #include<stdio.h>
    using namespace std;
    
    long long int start[100005];//每盏灯開始亮时刻
    long long int End[100005];//每盏灯亮完时刻
    int n,q,a;
    long long int t;
    
    int work(long long int ask)//每次二分查找函数
    {
        int p=1;
        int p1=1;
        int p2=n;
        while(ask<start[p]||ask>End[p])
        {
            p=(p1+p2)/2;
            if(ask>=start[p]&&ask<=End[p])
            {
                break;
            }else if(ask>=start[p1]&&ask<=End[p1])
            {
                p=p1;
                break;
            }else if(ask>=start[p2]&&ask<=End[p2])
            {
                p=p2;
                break;
            }else if(ask<start[p]&&ask>End[p1])
            {
                p2=p;
            }else if(ask>End[p]&&ask<start[p2])
            {
                p1=p;
            }
        }
    
        return p;//p就是那盏灯
    }
    
    int main()
    {
        scanf("%d%d",&n,&q);
        start[1]=0;
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&a);
            End[i]=start[i]+a-1;
            start[i+1]=start[i]+a;
        }
        while(q--)
        {
            scanf("%I64d",&t);
            printf("%d
    ",work(t%start[n+1]));
        }
        return 0;
    }
    
    


     

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  • 原文地址:https://www.cnblogs.com/lytwajue/p/7222928.html
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