zoukankan      html  css  js  c++  java
  • [GeeksForGeeks] Sort an array in wave form

    Given an unsorted array of integers, sort the array into a wave like array. An array arr[0...n-1] is sorted in wave form

    if arr[0] >= arr[1] <= arr[2] >= arr[3] <= arr[4] >= ....

    Solution 1. O(n * logn) runtime, using sorting 

    1. sort the input array.

    2. swap all adjacent elements.

     1 import java.util.Arrays;
     2 public class Solution {
     3     public void sortInWaveForm(int[] nums){
     4         if(nums == null){
     5             return;
     6         }
     7         Arrays.sort(nums);
     8         for(int i = 0; i < nums.length - 1; i += 2){
     9             swap(nums, i, i + 1);
    10         }
    11     }
    12     private void swap(int[] nums, int idx1, int idx2){
    13         int temp = nums[idx1];
    14         nums[idx1] = nums[idx2];
    15         nums[idx2] = temp;
    16     }
    17     public static void main(String[] args){
    18         int[] nums1 = {3, 4, 2, 1, 5};
    19         int[] nums2 = {3, 5, 2, 4, 1, 6};
    20         Solution sol = new Solution();
    21         sol.sortInWaveForm(nums1);
    22         for(int i = 0; i < nums1.length; i++){
    23             System.out.print(nums1[i] + " ");
    24         }
    25         System.out.println();
    26         sol.sortInWaveForm(nums2);
    27         for(int i = 0; i < nums2.length; i++){
    28             System.out.print(nums2[i] + " ");
    29         }    
    30     }
    31 }

    Solution 2. O(n) runtime

    Idea:  we only need to make sure that all even positioned elements are >= than their adjacent odd elements. No need to worry about odd positioned elements.

    Algorithm:

    Traverse all even positioned elements of input array, and do the following.

    a. If current element is smaller than previous odd positioned element, swap previous and current.

    b. If current element is smaller than next odd positioned element, swap next and current.

     1 public class Solution {
     2     public void sortInWaveForm(int[] nums){
     3         if(nums == null){
     4             return;
     5         }
     6         for(int i = 0; i < nums.length; i += 2){
     7             if(i > 0 && nums[i] < nums[i - 1]){
     8                 swap(nums, i, i - 1);
     9             }
    10             if(i < nums.length - 1 && nums[i] < nums[i + 1]){
    11                 swap(nums, i, i + 1);
    12             }
    13         }
    14     }
    15     private void swap(int[] nums, int idx1, int idx2){
    16         int temp = nums[idx1];
    17         nums[idx1] = nums[idx2];
    18         nums[idx2] = temp;
    19     }
    20 }
  • 相关阅读:
    关于C的一些理解
    Linux下/proc目录简介
    python学习链接
    “段寄存器”的故事[转](彻底搞清内存段/elf段/实模式保护模式以及段寄存器)
    内核态与用户态
    bzoj1087: [SCOI2005]互不侵犯King 状压dp
    bzoj1007: [HNOI2008]水平可见直线 单调栈维护凸壳
    bzoj1015: [JSOI2008]星球大战starwar
    bzoj1002: [FJOI2007]轮状病毒 生成树计数
    bzoj1013: [JSOI2008]球形空间产生器sphere
  • 原文地址:https://www.cnblogs.com/lz87/p/7208992.html
Copyright © 2011-2022 走看看