0-1背包问题（经典）HDU2602 Bone Collector

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 36479    Accepted Submission(s): 15052

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

 

Sample Input

1 5 10 1 2 3 4 5 5 4 3 2 1

 

Sample Output

14

 

Author

Teddy

 

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest

 

 AC code:

#include <iostream>
using namespace std;
int main()
{
    int t,n,v,i,j;
    int weight[1005],value[1005],record[1005];
    cin>>t;
    while(t--)
    {
        memset(record,0,sizeof(record));
      cin>>n>>v;
      for(i=0; i<n; i++)
          cin>>value[i];
      for(i=0; i<n; i++)
          cin>>weight[i];
      for(i=0; i<n; i++)
      {
          for(j=v;j>=weight[i]; j--)
          {
              if(record[j-weight[i]]+value[i]>record[j])
                  record[j] = record[j-weight[i]]+value[i];
          }
      }
      cout<<record[v]<<endl;
    }

    return 0;
}