zoukankan      html  css  js  c++  java
  • POJ 1163 The Triangle

    The Triangle
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 33476   Accepted: 19865

    Description

    7
    3 8
    8 1 0
    2 7 4 4
    4 5 2 6 5

    (Figure 1)
    Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right. 

    Input

    Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.

    Output

    Your program is to write to standard output. The highest sum is written as an integer.

    Sample Input

    5
    7
    3 8
    8 1 0 
    2 7 4 4
    4 5 2 6 5

    Sample Output

    30
    #include <stdio.h>
    #include <iostream>
    #include <string.h>
    using namespace std;
    
    int maze[105][105];
    int dp[105][105];
    
    int main()
    {
        int n;
        scanf("%d", &n);
        for (int i = 1; i <= n; i++)
        {
            for (int j = 1; j <= i; j++)
            {
                scanf("%d", &maze[i][j]);
            }
        }
        for (int i = 1; i <= n; i++)
        {
            for (int j = 1; j <= i; j++)
            {
                dp[i][j] = max(dp[i - 1][j], dp[i - 1][j - 1]) + maze[i][j];
            }
        }
        int Max = -10000000;
        for (int i = 1; i <= n; i++)
        {
            Max = max(Max, dp[n][i]);    
        }
        printf("%d
    ", Max);
        return 0;
    }
  • 相关阅读:
    Java——HTTPServletRequest的使用
    JavaWeb——HttpServletResponse的使用,文件下载
    JavaWeb——Servlet简介
    JavaWeb——TomCat服务器
    HTTP与HTTPS
    Java——DBCP连接池
    Java——JDBC连接MySQL
    Java——线程锁,死锁,等待唤醒机制
    LeetCode118. 杨辉三角
    LeetCode66. 加一
  • 原文地址:https://www.cnblogs.com/lzmfywz/p/3207558.html
Copyright © 2011-2022 走看看