zoukankan      html  css  js  c++  java
  • bzoj4034

    http://www.lydsy.com/JudgeOnline/problem.php?id=4034

    树链剖分。

    跟NOI2015的“软件包管理”一模一样。。。。。

    河南的爽死了。。。。。。

    #include<cstdio>
    #include<cstdlib>
    #include<iostream>
    #include<fstream>
    #include<algorithm>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<queue>
    #include<stack>
    #include<map>
    #include<utility>
    #include<set>
    #include<bitset>
    #include<vector>
    #include<functional>
    #include<deque>
    #include<cctype>
    #include<climits>
    #include<complex>
    //#include<bits/stdc++.h>适用于CF,UOJ,但不适用于poj
     
    using namespace std;
    
    typedef long long LL;
    typedef double DB;
    typedef pair<int,int> PII;
    typedef complex<DB> CP;
    
    #define mmst(a,v) memset(a,v,sizeof(a))
    #define mmcy(a,b) memcpy(a,b,sizeof(a))
    #define fill(a,l,r,v) fill(a+l,a+r+1,v)
    #define re(i,a,b)  for(i=(a);i<=(b);i++)
    #define red(i,a,b) for(i=(a);i>=(b);i--)
    #define ire(i,x) for(typedef(x.begin()) i=x.begin();i!=x.end();i++)
    #define fi first
    #define se second
    #define m_p(a,b) make_pair(a,b)
    #define SF scanf
    #define PF printf
    #define two(k) (1<<(k))
    
    template<class T>inline T sqr(T x){return x*x;}
    template<class T>inline void upmin(T &t,T tmp){if(t>tmp)t=tmp;}
    template<class T>inline void upmax(T &t,T tmp){if(t<tmp)t=tmp;}
    
    const DB EPS=1e-9;
    inline int sgn(DB x){if(abs(x)<EPS)return 0;return(x>0)?1:-1;}
    const DB Pi=acos(-1.0);
    
    inline int gint()
      {
            int res=0;bool neg=0;char z;
            for(z=getchar();z!=EOF && z!='-' && !isdigit(z);z=getchar());
            if(z==EOF)return 0;
            if(z=='-'){neg=1;z=getchar();}
            for(;z!=EOF && isdigit(z);res=res*10+z-'0',z=getchar());
            return (neg)?-res:res; 
        }
    inline LL gll()
      {
          LL res=0;bool neg=0;char z;
            for(z=getchar();z!=EOF && z!='-' && !isdigit(z);z=getchar());
            if(z==EOF)return 0;
            if(z=='-'){neg=1;z=getchar();}
            for(;z!=EOF && isdigit(z);res=res*10+z-'0',z=getchar());
            return (neg)?-res:res; 
        }
    
    const int maxN=100000;
    
    int N,Q;
    int val[maxN+100];
    int now,first[maxN+100];
    struct Tedge{int v,next;}edge[2*maxN+100];
    
    inline void addedge(int u,int v){now++;edge[now].v=v;edge[now].next=first[u];first[u]=now;}
    
    int head,tail,que[maxN+100];
    int fa[maxN+100],size[maxN+100],heavyson[maxN+100],gao[maxN+100];
    int cnt,idx[maxN+100],l[maxN+100],r[maxN+100];
    int vis[maxN+100],top,sta[maxN+100],last[maxN+100];
    inline void build()
      {
          int i,j;
          que[head=tail=1]=1;
          while(head<=tail)
            {
                int u=que[head++],v;
                for(i=first[u],v=edge[i].v;i!=-1;i=edge[i].next,v=edge[i].v)if(v!=fa[u])fa[que[++tail]=v]=u;
            }
          red(j,tail,1)
            {
                int u=que[j],v;
                size[u]=1;
                for(i=first[u],v=edge[i].v;i!=-1;i=edge[i].next,v=edge[i].v)if(v!=fa[u])size[u]+=size[v];
            }
          re(j,1,tail)
            {
                int u=que[j],v,heavy=-1;
                for(i=first[u],v=edge[i].v;i!=-1;i=edge[i].next,v=edge[i].v)if(v!=fa[u])
                  if(heavy==-1 || size[heavy]<size[v]) heavy=v;
                heavyson[u]=heavy;
            }
          vis[sta[top=1]=1]=1;
          last[1]=first[1];
          idx[1]=++cnt;
          gao[1]=1;
          while(top>=1)
            {
                int u=sta[top],i=last[u],v;
                if(heavyson[u]!=-1 && !vis[heavyson[u]])
                  {
                      v=heavyson[u];
                          vis[sta[++top]=v]=1;
                            last[v]=first[v];
                            idx[v]=++cnt;
                            gao[v]=gao[u];
                        }
                    else
                      for(v=edge[i].v;i!=-1;i=edge[i].next,v=edge[i].v)if(v!=fa[u] && !vis[v])
                        {
                            vis[sta[++top]=v]=1;
                                last[v]=first[v];
                                idx[v]=++cnt;
                                gao[v]=v;
                                last[u]=edge[i].next;
                                break;
                            }
                    if(i==-1)top--;
                }
            red(j,tail,1)
              {
                  int u=que[j],v;
                  l[u]=r[u]=idx[u];
                  for(i=first[u],v=edge[i].v;i!=-1;i=edge[i].next,v=edge[i].v)if(v!=fa[u])upmin(l[u],l[v]),upmax(r[u],r[v]);
              }
        }
    
    struct Ttree{LL v,add;}tr[4*maxN+1000];
    inline void down(int rt,int l,int r,int mid)
      {
          if(tr[rt].add==0)return;
          LL add=tr[rt].add;
          tr[rt*2].add+=add;tr[rt*2].v+=add*LL(mid-l+1);
          tr[rt*2+1].add+=add;tr[rt*2+1].v+=add*LL(r-mid);
          tr[rt].add=0;
      }
    inline void update(int rt,int l,int r,int x,int y,LL val)
      {
          if(l>r || x>y || y<l || r<x)return;
          if(x<=l && r<=y){tr[rt].add+=val;tr[rt].v+=val*LL(r-l+1);return;}
            int mid=(l+r)>>1;
          down(rt,l,r,mid);
          update(rt*2,l,mid,x,y,val);
          update(rt*2+1,mid+1,r,x,y,val);
          tr[rt].v=tr[rt*2].v+tr[rt*2+1].v;
      }
    inline LL ask(int rt,int l,int r,int x,int y)
      {
          if(l>r || x>y || y<l || r<x)return 0;
          if(x<=l && r<=y)return tr[rt].v;
          int mid=(l+r)>>1;
          down(rt,l,r,mid);
          return ask(rt*2,l,mid,x,y)+ask(rt*2+1,mid+1,r,x,y);
      }
    
    inline LL query(int x)
      {
          LL res=0;
          while(x)
            {
                res+=ask(1,1,N,idx[gao[x]],idx[x]);
                x=fa[gao[x]];
            }
          return res;
      }
    
    int main()
      {
          freopen("bzoj4034.in","r",stdin);
          freopen("bzoj4034.out","w",stdout);
          int i;
          N=gint();Q=gint();
          re(i,1,N)val[i]=gint();
          now=-1;mmst(first,-1);
          re(i,1,N-1){int u=gint(),v=gint();addedge(u,v);addedge(v,u);}
          build();
          re(i,1,N)update(1,1,N,idx[i],idx[i],LL(val[i]));
          while(Q--)
            {
                int type=gint(),x,a;
                switch(type)
                  {
                      case 1:
                          x=gint();a=gint();
                          update(1,1,N,idx[x],idx[x],LL(a));
                      break;
                      case 2:
                          x=gint();a=gint();
                          update(1,1,N,l[x],r[x],LL(a));
                      break;
                      case 3:
                          x=gint();
                          //PF("%lld
    ",query(x));
                          cout<<query(x)<<endl;
                      break;
                  }
            }
          return 0;
      }
    View Code
  • 相关阅读:
    git命令_保存本地变更+拉取+合并代码+推送代码到远程仓+添加CI触发器变量
    debian_linux_apt-get命令_dpkg命令
    debian_linux系统_访问真实环境rancher_证书问题相关_https相关_使用kubectl命令行查看资源时报错:Unable to connect to the server: x509: certificate signed by unknown authority
    linux_xargs入门介绍_及和for循环命令区别
    技术实践丨GaussDB(DWS)运维管理功能“升级”的原理和使用
    华为云数据安全中心正式公测,8大核心数据安全能力守护你的数据
    华为鲲鹏专家解读:90%代码如何移植到鲲鹏平台
    数据库技术丨GaussDB(DWS)数据同步状态查看方法
    你掉进过“伪敏捷”的陷阱吗?
    拯救深度学习:标注数据不足下的深度学习方法
  • 原文地址:https://www.cnblogs.com/maijing/p/4751007.html
Copyright © 2011-2022 走看看