sprngmvc+restFul 请求报错：404

服务端代码

control类

    @RequestMapping(value="getUser",method = RequestMethod.POST)
    @ResponseBody
    public User getUser(HttpServletRequest request){
        String name = request.getParameter("name");
        String age = request.getParameter("age");
        User user = new User();
        user.setPassWord("123123");
        user.setUserName("asdasd");
        return user;
    }

spring核心控制器

    <!--配置Springmvc核心控制器 -->
    <servlet>
        <servlet-name>springmvc</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>classpath:springMVC.xml</param-value>
        </init-param>
    </servlet>
    <servlet-mapping>
        <servlet-name>springmvc</servlet-name>
        <url-pattern>*.action</url-pattern>
    </servlet-mapping>

客户端代码

import com.alibaba.fastjson.JSONObject;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.junit.Test;

import java.io.IOException;

public class HttpclientTest {
    @Test
    public void httpReqUrl()
            throws ClientProtocolException, IOException {
        String url = "http://localhost:8080/ssm/user/getUser";
        JSONObject json = new JSONObject();
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost method = new HttpPost(url);
        // 接收参数json列表
        JSONObject jsonParam = new JSONObject();

        StringEntity entity = new StringEntity(jsonParam.toString(), "utf-8");//解决中文乱码问题
        entity.setContentEncoding("UTF-8");
        entity.setContentType("application/json");
        method.setEntity(entity);

        HttpResponse result = httpClient.execute(method);
        // 请求结束，返回结果
        String resData = EntityUtils.toString(result.getEntity());
        JSONObject resJson = json.parseObject(resData);
        System.out.printf(":::"+resJson.toString());
    }
}

 调用报错：http.404

报错原因：服务端配置的核心控制器，只拦截以 “.action”结尾的请求

解决方案：将服务端核心控制器配置“<url-pattern>*.action</url-pattern>”改为“<url-pattern>/</url-pattern>”