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  • ZOJ Problem Set–1858 Soundex

    Time Limit: 2 Seconds      Memory Limit: 65536 KB


    Soundex coding groups together words that appear to sound alike based on their spelling. For example, "can" and "khawn", "con" and "gone" would be equivalent under Soundex coding.
    Soundex coding involves translating each word into a series of digits in which each digit represents a letter:

    1 represents B, F, P, or V
    2 represents C, G, J, K, Q, S, X, or Z
    3 represents D or T
    4 represents L
    5 represents M or N
    6 represents R

    The letters A, E, I, O, U, H, W, and Y are not represented in Soundex coding, and repeated letters with the same code digit are represented by a single instance of that digit. Words with the same Soundex coding are considered equivalent.

    Input
    Each line of input contains a single word, all upper case, less than 20 letters long.

    Output

    For each line of input, produce a line of output giving the Soundex code.

    Sample Input
    KHAWN
    PFISTER
    BOBBY

    Sample Output
    25
    1236
    11


    Source: University of Waterloo Local Contest 1999.09.25

    #include<iostream>
    
    #include<string>
    
    using namespace std;
    
    int main(void)
    
    {
    
      string uword;
    
      while(cin>>uword)
    
      {
    
        int preI = 0, crtI = 0;
    
        for(int i = 0; i < uword.length(); i++)
    
        {
    
          switch(uword[i])
    
          {
    
          case 'B':case 'F':case 'P':case 'V':
    
            crtI = 1;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          case 'C':case 'G':case 'J':case 'K':case 'Q':case 'S':case 'X':case 'Z':
    
            crtI = 2;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          case 'D':case 'T':
    
            crtI = 3;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          case 'L':
    
            crtI = 4;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          case 'M':case 'N':
    
            crtI = 5;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          case 'R':
    
            crtI = 6;
    
            if(preI != crtI)
    
            {
    
              cout<<crtI;
    
              preI = crtI;
    
            }
    
            break;
    
          default:
    
            preI = 0;
    
            break;
    
          }
    
        }
    
        cout<<endl;
    
      }
    
      return 0;
    
    }
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  • 原文地址:https://www.cnblogs.com/malloc/p/2487731.html
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