zoukankan      html  css  js  c++  java
  • ZOJ Problem Set–1970 All in All

    Time Limit: 2 Seconds      Memory Limit: 65536 KB


    You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string.

    Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.

    Input

    The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF.

    Output

    For each test case output, print "Yes" if s is a subsequence of t or "No" if not.

    Sample Input

    sequence subsequence
    person compression
    VERDI vivaVittorioEmanueleReDiItalia
    caseDoesMatter CaseDoesMatter

    Sample Output

    Yes
    No
    Yes
    No


    Source: University of Ulm Local Contest 2002

      1: #include<iostream>
    
      2: #include<string>
    
      3: using namespace std;
    
      4: int main(void)
    
      5: {
    
      6:   string s,t;
    
      7:   while(cin>>s>>t)
    
      8:   {
    
      9:     int preIndex = -1;
    
     10:     bool no = false;
    
     11:     for(int i = 0; i < s.length(); i++)
    
     12:     {
    
     13:       int index = t.find_first_of(s[i], preIndex + 1);
    
     14:       if(index == string::npos)
    
     15:       {
    
     16:         cout<<"No"<<endl;
    
     17:         no = true;
    
     18:         break;
    
     19:       }
    
     20:       preIndex = index;
    
     21:     }
    
     22:     if(!no)
    
     23:       cout<<"Yes"<<endl;
    
     24:   }
    
     25:   return 0;
    
     26: }
  • 相关阅读:
    老人与小孩
    搭讪
    VIM 如何使用系统的剪切板
    Linux 下如何安装 .rpm 文件
    Linux 下如何安装 .bin 文件
    Tomorrow Is A New Day
    Hive 学习(五) Hive之HSQL基础
    Hive 学习(二) hive安装
    Hive 学习(四) Hive的数据类型
    Hive 学习(三) Hive的DDL操作
  • 原文地址:https://www.cnblogs.com/malloc/p/2494449.html
Copyright © 2011-2022 走看看