1646. Get Maximum in Generated Array (E)

Get Maximum in Generated Array (E)

题目

You are given an integer n. An array nums of length n + 1 is generated in the following way:

• nums[0] = 0
• nums[1] = 1
• nums[2 * i] = nums[i] when 2 <= 2 * i <= n
• nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n

Return the maximum integer in the array nums.

Example 1:

Input: n = 7
Output: 3
Explanation: According to the given rules:
  nums[0] = 0
  nums[1] = 1
  nums[(1 * 2) = 2] = nums[1] = 1
  nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
  nums[(2 * 2) = 4] = nums[2] = 1
  nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
  nums[(3 * 2) = 6] = nums[3] = 2
  nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.

Example 2:

Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0], nums[1], and nums[2] is 1.

Example 3:

Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0], nums[1], nums[2], and nums[3] is 2.

Constraints:

• 0 <= n <= 100

---

题意

按照指定规则生成数组，并求其中的最大值。

思路

直接模拟生成整个数组。

---

代码实现

Java

class Solution {
    public int getMaximumGenerated(int n) {
        if (n <= 1) {
            return n;
        }
        
        int max = 1;
        List<Integer> list = new ArrayList<>();
        list.add(0);
        list.add(1);
        
        for (int i = 2; i <= n; i++) {
            int num = i % 2 == 0 ? list.get(i / 2) : list.get(i / 2) + list.get(i / 2 + 1);
            max = Math.max(max, num);
            list.add(num);
        }
        
        return max;
    }
}