1001
题意:中文题
思路:p-1的因子个数
AC代码:
#include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set" #include "map" #include "algorithm" #include "stdio.h" #include "math.h" #pragma comment(linker, "/STACK:102400000,102400000") #define ll long long #define endl (" ") #define bug(x) cout<<x<<" "<<"UUUUU"<<endl; #define mem(a,x) memset(a,x,sizeof(a)) #define mp(x,y) make_pair(x,y) #define pb(x) push_back(x) #define ft first #define sd second #define lrt (rt<<1) #define rrt (rt<<1|1) using namespace std; const long long INF = 1e18+1LL; const int inf = 1e9+1e8; const int N=1e5+100; const ll mod=1e9+7; ll p,ans; int main(){ //ios::sync_with_stdio(false),cin.tie(0),cout.tie(0); int T; cin>>T; while(T--){ cin>>p; ans=0; for(ll i=1; i*i<=p-1; ++i){ if((p-1)%i==0){ if((p-1)/i!=i) ans++; ans++; } } cout<<ans<<endl; } return 0; }