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  • Educational Codeforces Round 26 B

    Flag of Berland

    题意:

    思路:模拟

    AC代码:

    #include "iostream"
    #include "iomanip"
    #include "string.h"
    #include "stack"
    #include "queue"
    #include "string"
    #include "vector"
    #include "set"
    #include "map"
    #include "algorithm"
    #include "stdio.h"
    #include "math.h"
    #pragma comment(linker, "/STACK:102400000,102400000")
    #define bug(x) cout<<x<<" "<<"UUUUU"<<endl;
    #define mem(a,x) memset(a,x,sizeof(a))
    #define step(x) fixed<< setprecision(x)<<
    #define mp(x,y) make_pair(x,y)
    #define pb(x) push_back(x)
    #define ll long long
    #define endl ("
    ")
    #define ft first
    #define sd second
    #define lrt (rt<<1)
    #define rrt (rt<<1|1)
    using namespace std;
    const long long INF = 1e18+1LL;
    const int inf = 1e9+1e8;
    const int N=1e5+100;
    const ll mod=1e9+7;
    
    char s[105][105];
    int n,m,r,b,g,mc[150];
    int main(){
        ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
        cin>>n>>m;
        for(int i=1; i<=n; ++i){
            cin>>s[i]+1;
        }
        int f=0,flag=0,mk=0;
        for(int i=2; i<=m; ++i){
            if(s[1][i]!=s[1][i-1]){
                f=1;
                break;
            }
        }
        s[0][1]='O',s[1][0]='O';
        if(!f){
            for(int i=1; i<=n; ++i){
                mc[s[i][1]]++;
                if(s[i][1]!=s[i-1][1]) mk++;
                for(int j=2; j<=m; ++j){
                    if(s[i][j]!=s[i][j-1]){
                        cout<<"NO";
                        return 0;
                    }
                }
            }
        }
        else{
            for(int j=1; j<=m; ++j){
                mc[s[1][j]]++;
                if(s[1][j]!=s[1][j-1]) mk++;
                for(int i=2; i<=n; ++i){
                    if(s[i][j]!=s[i-1][j]){
                        cout<<"NO";
                        return 0;
                    }
                }
            }
        }
        if(mk!=3 || mc['R']!=mc['B'] || mc['B']!=mc['G']){
            cout<<"NO";
            return 0;
        } //cout<<mk<<" "<<mc['R']<<" "<<mc['B']<<" "<<mc['G']<<endl;
        cout<<"YES";
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/max88888888/p/7365072.html
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