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  • hdu 1176 简单递推

    HDU 1176

    题意:中文题

    思路:简单递推

    AC代码:

    #include "iostream"
    #include "iomanip"
    #include "string.h"
    #include "stack"
    #include "queue"
    #include "string"
    #include "vector"
    #include "set"
    #include "map"
    #include "algorithm"
    #include "stdio.h"
    #include "math.h"
    #pragma comment(linker, "/STACK:102400000,102400000")
    #define bug(x) cout<<x<<" "<<"UUUUU"<<endl;
    #define mem(a,x) memset(a,x,sizeof(a))
    #define step(x) fixed<< setprecision(x)<<
    #define mp(x,y) make_pair(x,y)
    #define pb(x) push_back(x)
    #define ll long long
    #define endl ("
    ")
    #define ft first
    #define sd second
    #define lrt (rt<<1)
    #define rrt (rt<<1|1)
    using namespace std;
    const long long INF = 1e18+1LL;
    const int inf = 1e9+1e8;
    const int N=1e5+100;
    const ll mod=1e9+7;
    
    int n,dp[3][11];
    int M[N][11];
    int re(int t, int x){
        return M[t][x];
    }
    int main(){
        ios::sync_with_stdio(false),cin.tie(0),cout.tie(0);
        while(cin>>n&&n){
            int tm=0; mem(dp,0), mem(M,0);
            for(int i=1; i<=n; ++i){
                int t,x; cin>>x>>t;
                M[t][x]++; tm=max(tm,t);
            }
            dp[1][4]=re(1,4),dp[1][5]=re(1,5),dp[1][6]=re(1,6);
            int cur=1;
            for(int i=1; i<tm; ++i,cur^=1){
                for(int j=0; j<=10; ++j){
                    dp[cur^1][j]=max(dp[cur^1][j],dp[cur][j]+re(i+1,j));
                    if(j-1>=0) dp[cur^1][j-1]=max(dp[cur^1][j-1],dp[cur][j]+re(i+1,j-1));
                    if(j+1<=10) dp[cur^1][j+1]=max(dp[cur^1][j+1],dp[cur][j]+re(i+1,j+1));
                }
            }
            int ans=0;
            for(int i=0; i<=10; ++i) ans=max(ans,dp[cur][i]);
            cout<<ans<<endl;
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/max88888888/p/7365179.html
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