Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Notes:
- You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
思路:用两个stack去实现
class MyQueue { Stack<Integer> stack1=new Stack<Integer>(); //主 Stack<Integer> stack2=new Stack<Integer>(); //辅 // Push element x to the back of queue. public void push(int x) { stack1.push(x); } // Removes the element from in front of queue. public void pop() { while(!stack1.isEmpty()) { stack2.push(stack1.pop()); } if(!stack2.isEmpty()) stack2.pop(); while(!stack2.isEmpty()) { stack1.push(stack2.pop()); } } // Get the front element. public int peek() { int ret=0; while(!stack1.isEmpty()) { stack2.push(stack1.pop()); } if(!stack2.isEmpty()) { ret=stack2.peek(); } while(!stack2.isEmpty()) { stack1.push(stack2.pop()); } return ret; } // Return whether the queue is empty. public boolean empty() { return stack1.isEmpty(); } }
这里每次pop和peek操作都会将stack1转到stack2中,比较麻烦。再考虑下可以不用发给转来转去,stack1可以作为队尾,stack2可以作为对首的
class MyQueue { Stack<Integer> stack1=new Stack<Integer>(); //主 Stack<Integer> stack2=new Stack<Integer>(); //辅 // Push element x to the back of queue. public void push(int x) { stack1.push(x); } // Removes the element from in front of queue. public void pop() { if(!stack2.isEmpty()) stack2.pop(); else { while(!stack1.isEmpty()) { stack2.push(stack1.pop()); } if(!stack2.isEmpty()) stack2.pop(); } } // Get the front element. public int peek() { int ret=0; if(!stack2.isEmpty()) ret=stack2.peek(); else { while(!stack1.isEmpty()) { stack2.push(stack1.pop()); } if(!stack2.isEmpty()) ret=stack2.peek(); } return ret; } // Return whether the queue is empty. public boolean empty() { return stack1.isEmpty() && stack2.isEmpty(); } }