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  • SOJ 1041. Pushing Boxes

    题目大意:一矩形区域中有若干个箱子,每次能从上下左右四个方向推箱子,被推的箱子往前移动,但是不能被挤爆。

    解题思路:直接模拟。

    代码如下:

      1 #include <cstdio>
      2 #include <iostream>
      3 #include <string>
      4 #include <algorithm>
      5 using namespace std;
      6 const int maxd = 25;
      7 
      8 bool matrix[maxd][maxd];    // matrix[i][j] == true 表示位置(i,j)有内容
      9 int vertical[maxd];
     10 int horizonal[maxd];
     11 
     12 
     13 void init(const int &rows, const int &cols) {
     14     for (int r = 0; r <= rows; ++r)
     15         for (int c = 0; c <= cols; ++c)
     16             matrix[r][c] = false;
     17 }
     18 
     19 void fillRight(const int &r, const int &c) {
     20     if (matrix[r][c]) {
     21         fillRight(r, c + 1);
     22     } else {
     23         matrix[r][c] = true;
     24     }
     25 }
     26 
     27 void fillLeft(const int &r, const int &c) {
     28     if (matrix[r][c]) {
     29         fillLeft(r, c - 1);
     30     } else {
     31         matrix[r][c] = true;
     32     }
     33 }
     34 
     35 void fillDown(const int &r, const int &c) {
     36     if (matrix[r][c]) {
     37         fillDown(r + 1, c);
     38     } else {
     39         matrix[r][c] = true;
     40     }
     41 }
     42 
     43 void fillUp(const int &r, const int &c) {
     44     if (matrix[r][c]) {
     45         fillUp(r - 1, c);
     46     } else {
     47         matrix[r][c] = true;
     48     }
     49 }
     50 
     51 int main() {
     52     int t = 0;
     53     int rows, cols;
     54     string right("right");
     55     string left("left");
     56     string down("down");
     57     string up("up");
     58     string done("done");
     59 
     60     while (++t, scanf("%d%d", &rows, &cols), rows && cols) {
     61         init(rows, cols);
     62         int n;
     63         scanf("%d", &n);
     64         int row, col;
     65         for (int i = 0; i < n; ++i) {
     66             scanf("%d%d", &row, &col);
     67             matrix[row][col] = true;
     68         }
     69 
     70         string op;
     71         int opNum;
     72         while (cin >> op, op != done) {
     73             cin >> opNum;
     74             for (int i = 0; i < rows; ++i) horizonal[i] = 0;
     75             for (int i = 0; i < cols; ++i) vertical[i] = 0;
     76             for (int r = 0; r < rows; ++r) {
     77                 for (int c = 0; c < cols; ++c) {
     78                     if (matrix[r][c]) {
     79                         ++horizonal[r];
     80                         ++vertical[c];
     81                     }
     82                 }
     83             }
     84             int maxHorizonal = 0, maxVertical = 0;
     85             for (int i = 0; i < rows; ++i) maxHorizonal = max(maxHorizonal, horizonal[i]);
     86             for (int i = 0; i < cols; ++i) maxVertical = max(maxVertical, vertical[i]);
     87 
     88             if (op == left) {
     89                 int bound = min(opNum, cols - maxHorizonal);
     90                 int begin = cols - 1, end = begin - bound;
     91                 int count = 0;
     92                 for (int r = 0; r < rows; ++r) {
     93                     for (int c = begin; c > end; --c) {
     94                         if (matrix[r][c]) {
     95                             matrix[r][c] = false;
     96                             fillLeft(r, end - count);
     97                         }
     98                     }
     99                 }
    100             } else if (op == right) {
    101                 int bound = min(opNum, cols - maxHorizonal);
    102                 int begin = 0, end = bound;    // 左闭右开
    103                 int count = 0;
    104                 for (int r = 0; r < rows; ++r) {
    105                     for (int c = begin; c < end; ++c) {
    106                         if (matrix[r][c]) {
    107                             matrix[r][c] = false;    // 撤销位置中的物质
    108                             fillRight(r, end + count);
    109                         }
    110                     }
    111                 }
    112             } else if (op == up) {
    113                 int bound = min(opNum, rows - maxVertical);
    114                 int begin = rows - 1, end = begin - bound;
    115                 int count = 0;
    116                 for (int c = 0; c < cols; ++c) {
    117                     for (int r = begin; r > end; --r) {
    118                         if (matrix[r][c]) {
    119                             matrix[r][c] = false;
    120                             fillUp(end - count, c);
    121                         }
    122                     }
    123                 }
    124             } else if (op == down) {
    125                 int bound = min(opNum, rows - maxVertical);
    126                 int begin = 0, end = bound;
    127                 int count = 0;
    128                 for (int c = 0; c < cols; ++c) {
    129                     for (int r = begin; r < end; ++r) {
    130                         if (matrix[r][c]) {
    131                             matrix[r][c] = false;
    132                             fillDown(end + count, c);
    133                         }
    134                     }
    135                 }
    136             }
    137 
    138         }
    139         // 输出
    140         printf("Data set %d ends with boxes at locations", t);
    141         for (int r = 0; r < rows; ++r) {
    142             for (int c = 0; c < cols; ++c) {
    143                 if (matrix[r][c]) {
    144                     printf(" (%d,%d)", r, c);
    145                 }
    146             }
    147         }
    148         printf(".
    ");
    149     }
    150     return 0;
    151 }
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  • 原文地址:https://www.cnblogs.com/mchcylh/p/4972853.html
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