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  • sql 语句相对应 mongodb语句

    相信大家都对sql 非常熟悉的了,你能看明白sql语句是什么意思...一对比一下,很自然就知道是什么意思了

    mongodb api                http://api.mongodb.org/java/2.5-pre-/index.html

    SQL Statement Mongo Query Language Statement
    create table users(a number,b number) implicit; can be done explicitly
    insert into users (1,1) db.users.insert({a:1,b:1})
    select a,b from users db.users.find({},{a:1,b:1})
    slect * from users db.users.find()
    SELECT * FROM users WHERE age=33 db.users.find({age:33})
    SELECT a,b FROM users WHERE age=33 db.users.find({age:33}, {a:1,b:1})
    SELECT * FROM users WHERE age=33 ORDER BY name db.users.find({age:33}).sort({name:1})
    SELECT * FROM users WHERE age>33 db.users.find({'age':{$gt:33}})})
    SELECT * FROM users WHERE age<33 db.users.find({'age':{$lt:33}})})
    SELECT * FROM users WHERE name LIKE "%Joe%" db.users.find({name:/Joe/})
    SELECT * FROM users WHERE name LIKE "Joe%" db.users.find({name:/^Joe/})
    SELECT * FROM users WHERE age>33 AND age<=40 db.users.find({'age':{$gt:33,$lte:40}})})
    SELECT * FROM users ORDER BY name DESC db.users.find().sort({name:-1})
    CREATE INDEX myindexname ON users(name) db.users.ensureIndex({name:1})
    CREATE INDEX myindexname ON users(name,ts DESC) db.users.ensureIndex({name:1,ts:-1})
    SELECT * FROM users WHERE a=1 and b='q' db.users.find({a:1,b:'q'})
    SELECT * FROM users LIMIT 10 SKIP 20 db.users.find().limit(10).skip(20)
    SELECT * FROM users WHERE a=1 or b=2 db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } )
    SELECT * FROM users LIMIT 1 db.users.findOne()
    EXPLAIN SELECT * FROM users WHERE z=3 db.users.find({z:3}).explain()
    SELECT DISTINCT last_name FROM users db.users.distinct('last_name')
    SELECT COUNT(*y) FROM users db.users.count()
    SELECT COUNT(*y)FROM users where AGE > 30 db.users.find({age: {'$gt': 30}}).count()
    SELECT COUNT(AGE) from users db.users.find({age: {'$exists': true}}).count()
    UPDATE users SET a=1 WHERE b='q' db.users.update({b:'q'}, {$set:{a:1}}, false, true)
    UPDATE users SET a=a+2 WHERE b='q' db.users.update({b:'q'}, {$inc:{a:2}}, false, true)
    DELETE FROM users WHERE z="abc" db.users.remove({z:'abc'})
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  • 原文地址:https://www.cnblogs.com/meetrice/p/3000488.html
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