Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted in ascending from left to right.
- Integers in each column are sorted in ascending from top to bottom.
Example:
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5
, return true
.
Given target = 20
, return false
.
有序矩阵查找
C++:
1 class Solution { 2 public: 3 bool searchMatrix(vector<vector<int>>& matrix, int target) { 4 int n = matrix.size() ; 5 if (n == 0) 6 return false ; 7 int m = matrix[0].size() ; 8 int i = 0 ; 9 int j = m-1 ; 10 while(i < n && j >= 0){ 11 if (matrix[i][j] == target){ 12 return true ; 13 }else if (matrix[i][j] > target){ 14 j-- ; 15 }else{ 16 i++ ; 17 } 18 } 19 return false ; 20 } 21 };