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  • 240. Search a 2D Matrix II

    Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

    • Integers in each row are sorted in ascending from left to right.
    • Integers in each column are sorted in ascending from top to bottom.

    Example:

    Consider the following matrix:

    [
      [1,   4,  7, 11, 15],
      [2,   5,  8, 12, 19],
      [3,   6,  9, 16, 22],
      [10, 13, 14, 17, 24],
      [18, 21, 23, 26, 30]
    ]
    

    Given target = 5, return true.

    Given target = 20, return false.

    有序矩阵查找

    C++:

     1 class Solution {
     2 public:
     3     bool searchMatrix(vector<vector<int>>& matrix, int target) {
     4         int n = matrix.size() ;
     5         if (n == 0)
     6             return false ;
     7         int m = matrix[0].size() ;
     8         int i = 0 ;
     9         int j = m-1 ;
    10         while(i < n && j >= 0){
    11             if (matrix[i][j] == target){
    12                 return true ;
    13             }else if (matrix[i][j] > target){
    14                 j-- ;
    15             }else{
    16                 i++ ;
    17             }
    18         }
    19         return false ;
    20     }
    21 };
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  • 原文地址:https://www.cnblogs.com/mengchunchen/p/10275915.html
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