1 带IN关键字的子查询
#查询平均年龄在25岁以上的部门名
关键点部门名
以查询员工表的dep_id的结果 当作另外一条sql语句查询条件使用
in (sql语句)
mysql> select dep_id from employee group by dep_id having avg(age) >25 ; +--------+ | dep_id | +--------+ | 201 | | 202 | +--------+ 2 rows in set (0.00 sec)
mysql> select name from department where id in (select dep_id from employee group by dep_id having avg(age) >25) ; +--------------+ | name | +--------------+ | 人力资源 | | 销售 | +--------------+ 2 rows in set (0.00 sec)
#查看技术部员工姓名
mysql> select name from employee where dep_id in (select id from department where name = "技术") ; +-----------+ | name | +-----------+ | mike | | liwenzhou | +-----------+ 2 rows in set (0.00 sec)
#查看不足1人的部门名
查询部门id 这里的部门人数至少有1人以上
一个id 对应一个员工 有得id对应多个员工
mysql> select dep_id from employee ; +--------+ | dep_id | +--------+ | 200 | | 201 | | 201 | | 202 | | 200 | | 204 | +--------+ 6 rows in set (0.00 sec)
拿到是至少有一个人部门id 取反就是不足1人的部门id
mysql> select distinct dep_id from employee ; +--------+ | dep_id | +--------+ | 200 | | 201 | | 202 | | 204 | +--------+ 4 rows in set (0.00 sec)
取反
mysql> select name from department where id not in(select distinct dep_id from employee) ; +--------+ | name | +--------+ | 运营 | +--------+ 1 row in set (0.00 sec)