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  • Balloon Comes! hdu(小数位数处理)

    Balloon Comes! 
    Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)  
    Total Submission(s): 5402 Accepted Submission(s): 1722  
    
     
    Problem Description
    The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem.
    Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result. 
    Is it very easy? 
    Come on, guy! PLMM will send you a beautiful Balloon right now!
    Good Luck!
    
     
     
    Input
    Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator. 
    
     
     
    Output
    For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.
    
     
     
    Sample Input
    4
    + 1 2
    - 1 2
    * 1 2
    / 1 2 
     
    Sample Output
    3
    -1
    2
    0.50 
    package ACM1;
    
    import java.math.RoundingMode;
    import java.text.DecimalFormat;
    import java.util.Scanner;
    
    public class hdu1 {
        public static void main(String[]args)
        {
            Scanner scanner = new Scanner(System.in);
            int n = scanner.nextInt();
            
            for(int i=0;i<n;i++)
            {   
                
                String a = scanner.next();
                int b = scanner.nextInt();
                int c = scanner.nextInt();
                //double result = (double)b/(double)c;
                if(a.charAt(0)=='+')
                    System.out.println((b+c));
                else if(a.charAt(0)=='-')
                    System.out.println((b-c));
                else if(a.charAt(0)=='*')
                    System.out.println((b*c));
                else
                    {
                        if(b%c==0)
                            System.out.println((b/c));
                        else
                        {
                            DecimalFormat dc = new DecimalFormat("0.00");
                            //dc.setMaximumFractionDigits(2);
                            //dc.setGroupingSize(0);
                            //dc.setRoundingMode(RoundingMode.FLOOR);
                            //System.out.println(dc.format(b/(1.0*c)));//我不明白为什么这个样子不对
                            System.out.format("%.2f",(b/(1.0*c)) ).println();//为什么这个样子对
                            
                            
                        }
                    
                    
                    }
                    
                }
                
                
            }
            
        }
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  • 原文地址:https://www.cnblogs.com/mmlovejj/p/4457502.html
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