zoukankan      html  css  js  c++  java
  • Poj 3030 Nasty Hacks

    1.Link:

    http://poj.org/problem?id=3030

    2.Content:

    Nasty Hacks
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 12350   Accepted: 8537

    Description

    You are the CEO of Nasty Hacks Inc., a company that creates small pieces of malicious software which teenagers may use to fool their friends. The company has just finished their first product and it is time to sell it. You want to make as much money as possible and consider advertising in order to increase sales. You get an analyst to predict the expected revenue, both with and without advertising. You now want to make a decision as to whether you should advertise or not, given the expected revenues.

    Input

    The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, re and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: −106 ≤ re ≤ 106 and 0 ≤ c ≤ 106.

    Output

    Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference.

    Sample Input

    3
    0 100 70
    100 130 30
    -100 -70 40

    Sample Output

    advertise
    does not matter
    do not advertise

    Source

    3.Method:

    4.Code:

     1 #include<iostream>
     2 using namespace std;
     3 int main()
     4 {
     5     int i,n;
     6     int r,e,c;
     7     int result;
     8     cin>>n;
     9     for(i=0;i<n;i++)
    10     {
    11        cin>>r>>e>>c;
    12        result=e-c-r;
    13        if(result>0) cout<<"advertise"<<endl;
    14        else if(result<0) cout<<"do not advertise"<<endl;
    15        else cout<<"does not matter"<<endl;
    16     }
    17     //system("pause");
    18     return 1;
    19     
    20 }

    5.Reference:

  • 相关阅读:
    sersync 配合rsync实时同步备份
    全网实时热备inotify+rsync
    rsync定时同步配置
    NFS架构搭建详解
    visio2013密钥
    jekens介绍及服务搭建
    服务端开发新框架
    docker
    ymal
    linux部署环境配置
  • 原文地址:https://www.cnblogs.com/mobileliker/p/4068281.html
Copyright © 2011-2022 走看看