//复杂度log(n) #include <stdio.h> #include <string.h> #include <stdlib.h> #include <limits.h> #include <malloc.h> #include <ctype.h> #include <math.h> #include <string> #include <iostream> #include <algorithm> #include <queue> #include<cmath> using namespace std; #include <vector> const int MAXN = 100010; int tree[20][MAXN];//表示每层每个位置的值 int sorted[MAXN];//已经排序好的数 int toleft[20][MAXN];//toleft[p][i]表示第p层从1到i有数分入左边 void build(int l,int r,int dep) { if(l == r)return; int mid = (l+r)>>1; int same = mid - l + 1;//表示等于中间值而且被分入左边的个数 for(int i = l; i <= r; i++) //注意是l,不是one if(tree[dep][i] < sorted[mid]) same--; int lpos = l; int rpos = mid+1; for(int i = l;i <= r;i++) { if(tree[dep][i] < sorted[mid]) tree[dep+1][lpos++] = tree[dep][i]; else if(tree[dep][i] == sorted[mid] && same > 0) { tree[dep+1][lpos++] = tree[dep][i]; same--; } else tree[dep+1][rpos++] = tree[dep][i]; toleft[dep][i] = toleft[dep][l-1] + lpos - l; } build(l,mid,dep+1); build(mid+1,r,dep+1); } //查询区间第k大的数,[L,R]是大区间,[l,r]是要查询的小区间 //query(1,n,s,t,0,k):: s-t区间内第k大 int query(int L,int R,int l,int r,int dep,int k) { if(l == r)return tree[dep][l]; int mid = (L+R)>>1; int cnt = toleft[dep][r] - toleft[dep][l-1]; if(cnt >= k) { int newl = L + toleft[dep][l-1] - toleft[dep][L-1]; int newr = newl + cnt - 1; return query(L,mid,newl,newr,dep+1,k); } else { int newr = r + toleft[dep][R] - toleft[dep][r]; int newl = newr - (r-l-cnt); return query(mid+1,R,newl,newr,dep+1,k-cnt); } } int main() { int n,m; int T; scanf("%d",&T); while(T--) { scanf("%d%d",&n,&m); //------------------------------build memset(tree,0,sizeof(tree)); for(int i = 1;i <= n;i++) { scanf("%d",&tree[0][i]); sorted[i] = tree[0][i]; } sort(sorted+1,sorted+n+1); build(1,n,0); //------------------------------build int s,t,k; while(m--) { scanf("%d%d%d",&s,&t,&k); printf("%d ",query(1,n,s,t,0,k)); } } return 0; }