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  • [LOJ144] DFS 序 1

    为熟悉机房键盘而划水

    #include <bits/stdc++.h>
    using namespace std;
    #define int long long
    
    const int N = 4000005;
    
    int R;
    
    namespace seg {
    int a[N], src[N];
    
    void pushup(int p) { a[p] = a[p * 2] + a[p * 2 + 1]; }
    
    void build(int p, int l, int r) {
        if (l == r) {
            a[p] = src[l];
        } else {
            build(p * 2, l, (l + r) / 2);
            build(p * 2 + 1, (l + r) / 2 + 1, r);
            pushup(p);
        }
    }
    
    void modify(int p, int l, int r, int pos, int val) {
        if (l == r) {
            a[p] += val;
        } else {
            if (pos <= (l + r) / 2) {
                modify(p * 2, l, (l + r) / 2, pos, val);
            } else {
                modify(p * 2 + 1, (l + r) / 2 + 1, r, pos, val);
            }
            pushup(p);
        }
    }
    
    int query(int p, int l, int r, int ql, int qr) {
        if (l > qr || r < ql)
            return 0;
        if (l >= ql && r <= qr)
            return a[p];
        else {
            return query(p * 2, l, (l + r) / 2, ql, qr) + query(p * 2 + 1, (l + r) / 2 + 1, r, ql, qr);
        }
    }
    }  // namespace seg
    
    namespace tree {
    int dfn[N], fin[N], ind;
    vector<int> g[N];
    
    void dfs(int p) {
        dfn[p] = ++ind;
        for (int i = 0; i < g[p].size(); i++) {
            if (dfn[g[p][i]] == 0) {
                dfs(g[p][i]);
            }
        }
        fin[p] = ind;
    }
    
    void presolve() {
        ind = 0;
        dfs(R);
    }
    }  // namespace tree
    
    int n, m, t1, t2, t3, t4, val[N];
    
    signed main() {
        ios::sync_with_stdio(false);
        cin >> n >> m >> R;
        for (int i = 1; i <= n; i++) {
            cin >> val[i];
        }
        for (int i = 1; i < n; i++) {
            cin >> t1 >> t2;
            tree::g[t1].push_back(t2);
            tree::g[t2].push_back(t1);
        }
    
        tree::presolve();
    
        for (int i = 1; i <= n; i++) {
            seg::src[tree::dfn[i]] = val[i];
        }
    
        seg::build(1, 1, n);
    
        for (int i = 1; i <= m; i++) {
            cin >> t1 >> t2;
            if (t1 == 1) {
                cin >> t3;
                seg::modify(1, 1, n, tree::dfn[t2], t3);
            } else {
                cout << seg::query(1, 1, n, tree::dfn[t2], tree::fin[t2]) << endl;
            }
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/mollnn/p/11707430.html
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