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  • [AHOI2002] 芝麻开门

    (n^k) 的因子和, (n leq 2^{16}, k leq 20)

    Solution

    [prod_i frac{p_i^{q_ik+1}-1}{p_i-1} ]

    #include <bits/stdc++.h>
    using namespace std;
    
    const int maxlen = 105;
    
    class HP {
    public:
        int len, s[maxlen];
        HP() { (*this) = 0; }
        HP(int inte) { (*this) = inte; }
        HP(const char *str) { (*this) = str; }
        friend ostream &operator<<(ostream &cout, const HP &x);
        HP operator=(int inte);
        HP operator=(const char *str);
        HP operator=(const HP &b);
        HP operator*(const HP &b);
        HP operator+(const HP &b);
        HP operator-(const HP &b);
        HP operator/(const HP &b);
        HP operator%(const HP &b);
        bool operator<(const HP &b);
        bool operator>(const HP &b);
        int Compare(const HP &b);
    };
    
    ostream &operator<<(ostream &cout, const HP &x) {
        for (int i = x.len; i >= 1; i--) cout << x.s[i];
        return cout;
    }
    HP HP::operator=(const char *str) {
        len = (int)strlen(str);
        for (int i = 1; i <= len; i++) s[i] = str[len - i] - '0';
        return *this;
    }
    HP HP::operator=(int inte) {
        if (inte == 0) {
            len = 1;
            s[1] = 0;
            return (*this);
        }
        for (len = 0; inte > 0;) {
            s[++len] = inte % 10;
            inte /= 10;
        }
        return *this;
    }
    HP HP::operator=(const HP &b) {
        len = b.len;
        for (int i = 1; i <= len; i++) s[i] = b.s[i];
        return *this;
    }
    HP HP::operator*(const HP &b) {
        int i, j;
        HP c;
        c.len = len + b.len;
        for (i = 1; i <= c.len; i++) c.s[i] = 0;
        for (i = 1; i <= len; i++)
            for (j = 1; j <= b.len; j++) c.s[i + j - 1] += s[i] * b.s[j];
        for (i = 1; i < c.len; i++) {
            c.s[i + 1] += c.s[i] / 10;
            c.s[i] %= 10;
        }
        while (c.s[i]) {
            c.s[i + 1] = c.s[i] / 10;
            c.s[i] %= 10;
            i++;
        }
        while (i > 1 && !c.s[i]) i--;
        c.len = i;
        return c;
    }
    HP HP::operator+(const HP &b) {
        int i;
        HP c;
        c.s[1] = 0;
        for (i = 1; i <= len || i <= b.len || c.s[i]; i++) {
            if (i <= len)
                c.s[i] += s[i];
            if (i <= b.len)
                c.s[i] += b.s[i];
            c.s[i + 1] = c.s[i] / 10;
            c.s[i] %= 10;
        }
        c.len = i - 1;
        if (c.len == 0)
            c.len = 1;
        return c;
    }
    HP HP::operator-(const HP &b) {
        int i, j;
        HP c;
        for (i = 1, j = 0; i <= len; i++) {
            c.s[i] = s[i] - j;
            if (i <= b.len)
                c.s[i] -= b.s[i];
            if (c.s[i] < 0) {
                j = 1;
                c.s[i] += 10;
            } else
                j = 0;
        }
        c.len = len;
        while (c.len > 1 && !c.s[c.len]) c.len--;
        return c;
    }
    int HP::Compare(const HP &y) {
        if (len > y.len)
            return 1;
        if (len < y.len)
            return -1;
        int i = len;
        while ((i > 1) && (s[i] == y.s[i])) i--;
        return s[i] - y.s[i];
    }
    bool HP::operator<(const HP &b) {
        if (len < b.len)
            return 1;
        if (len > b.len)
            return 0;
        int i = len;
        while ((i > 1) && (s[i] == b.s[i])) i--;
        return s[i] < b.s[i];
    }
    bool HP::operator>(const HP &b) {
        if (len > b.len)
            return 1;
        if (len < b.len)
            return 0;
        int i = len;
        while ((i > 1) && (s[i] == b.s[i])) i--;
        return s[i] > b.s[i];
    }
    HP HP::operator/(const HP &b) {
        int i, j;
        HP d(0), c;
        for (i = len; i > 0; i--) {
            if (!(d.len == 1 && d.s[1] == 0)) {
                for (j = d.len; j > 0; j--) d.s[j + 1] = d.s[j];
                ++d.len;
            }
            d.s[1] = s[i];
            c.s[i] = 0;
            while ((j = d.Compare(b)) >= 0) {
                d = d - b;
                c.s[i]++;
                if (j == 0)
                    break;
            }
        }
        c.len = len;
        while ((c.len > 1) && (c.s[c.len] == 0)) c.len--;
        return c;
    }
    HP HP::operator%(const HP &b) {
        int i, j;
        HP d(0);
        for (i = len; i > 0; i--) {
            if (!(d.len == 1 && d.s[1] == 0)) {
                for (j = d.len; j > 0; j--) d.s[j + 1] = d.s[j];
                ++d.len;
            }
            d.s[1] = s[i];
            while ((j = d.Compare(b)) >= 0) {
                d = d - b;
                if (j == 0)
                    break;
            }
        }
        return d;
    }
    
    int n,k,a[99],b[99],top;
    HP ans;
    int main() {
        cin>>n>>k;
        ans=1;
        int t=n;
        for(int i=2;i<=n;i++) {
            if(t%i==0) {
                a[++top]=i;
            }
            while(t%i==0) {
                b[top]++;
                t/=i;
            }
        }
        for(int i=1;i<=top;i++) {
            HP tmp=1,xx;
            for(int j=1;j<=b[i]*k+1;j++) xx=a[i],tmp=tmp*xx;
            xx=1;
            tmp=tmp-xx;
            xx=a[i]-1;
            tmp=tmp/xx;
            ans=ans*tmp;
        }
        cout<<ans;
    }
    
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  • 原文地址:https://www.cnblogs.com/mollnn/p/12313606.html
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