zoukankan      html  css  js  c++  java
  • [CF546E] Soldier and Traveling

    [CF546E] Soldier and Traveling - 最大流

    Description

    (n le 100) 个城市,(m le 200) 条边。然后人只能从走相邻边相连的城市。现在给你初始城市的每一个人数,再给一组每个城市人数。询问是否可以从当前人数变换到给定人数。

    Solution

    直接对城市拆点为入点、出点后跑最大流

    #include <bits/stdc++.h>
    using namespace std;
    
    #define int long long
    
    #ifndef __FLOW_HPP__
    #define __FLOW_HPP__
    
    // v1.1     feat. edge query for Maxf
    
    #include <bits/stdc++.h>
    using namespace std;
    #define int long long
    
    namespace flowsolution
    {
        const int N = 100005;
        const int M = 1000005;
        const int inf = 1e+12;
    
        struct MaxflowSolution
        {
            int *dis, ans, cnt = 1, s, t, *pre, *next, *head, *val;
    
            MaxflowSolution()
            {
                cnt = 1;
                dis = new int[N];
                pre = new int[M];
                next = new int[M];
                head = new int[N];
                val = new int[M];
                fill(dis, dis + N, 0);
                fill(pre, pre + M, 0);
                fill(next, next + M, 0);
                fill(head, head + N, 0);
                fill(val, val + M, 0);
            }
    
            ~MaxflowSolution()
            {
                delete[] dis;
                delete[] pre;
                delete[] next;
                delete[] head;
                delete[] val;
            }
    
            std::queue<int> q;
            int make(int x, int y, int z)
            {
                pre[++cnt] = y, next[cnt] = head[x], head[x] = cnt, val[cnt] = z;
                int ret = cnt;
                pre[++cnt] = x, next[cnt] = head[y], head[y] = cnt;
                return ret;
            }
    
            int get_value(int x)
            {
                return val[x];
            }
    
            bool bfs()
            {
                fill(dis, dis + N, 0);
                q.push(s), dis[s] = 1;
                while (!q.empty())
                {
                    int x = q.front();
                    q.pop();
                    for (int i = head[x]; i; i = next[i])
                        if (!dis[pre[i]] && val[i])
                            dis[pre[i]] = dis[x] + 1, q.push(pre[i]);
                }
                return dis[t];
            }
    
            int dfs(int x, int flow)
            {
                if (x == t || !flow)
                    return flow;
                int f = flow;
                for (int i = head[x]; i; i = next[i])
                    if (val[i] && dis[pre[i]] > dis[x])
                    {
                        int y = dfs(pre[i], min(val[i], f));
                        f -= y, val[i] -= y, val[i ^ 1] += y;
                        if (!f)
                            return flow;
                    }
                if (f == flow)
                    dis[x] = -1;
                return flow - f;
            }
    
            int solve(int _s, int _t)
            {
                s = _s;
                t = _t;
                ans = 0;
                for (; bfs(); ans += dfs(s, inf))
                    ;
                return ans;
            }
        };
    
        struct CostflowSolution
        {
            struct Edge
            {
                int p = 0, c = 0, w = 0, next = -1;
            } * e;
            int s, t, tans, ans, cost, ind, *bus, qhead = 0, qtail = -1, *qu, *vis, *dist;
    
            CostflowSolution()
            {
                e = new Edge[M];
                qu = new int[M];
                bus = new int[N];
                vis = new int[N];
                dist = new int[N];
                fill(qu, qu + M, 0);
                fill(bus, bus + N, -1);
                fill(vis, vis + N, 0);
                fill(dist, dist + N, 0);
                ind = 0;
            }
    
            ~CostflowSolution()
            {
                delete[] e;
                delete[] qu;
                delete[] vis;
                delete[] dist;
            }
    
            void graph_link(int p, int q, int c, int w)
            {
                e[ind].p = q;
                e[ind].c = c;
                e[ind].w = w;
                e[ind].next = bus[p];
                bus[p] = ind;
                ++ind;
            }
    
            void make(int p, int q, int c, int w)
            {
                graph_link(p, q, c, w);
                graph_link(q, p, 0, -w);
            }
    
            int dinic_spfa()
            {
                qhead = 0;
                qtail = -1;
                fill(vis, vis + N, 0);
                fill(dist, dist + N, inf);
                vis[s] = 1;
                dist[s] = 0;
                qu[++qtail] = s;
                while (qtail >= qhead)
                {
                    int p = qu[qhead++];
                    vis[p] = 0;
                    for (int i = bus[p]; i != -1; i = e[i].next)
                        if (dist[e[i].p] > dist[p] + e[i].w && e[i].c > 0)
                        {
                            dist[e[i].p] = dist[p] + e[i].w;
                            if (vis[e[i].p] == 0)
                                vis[e[i].p] = 1, qu[++qtail] = e[i].p;
                        }
                }
                return dist[t] < inf;
            }
    
            int dinic_dfs(int p, int lim)
            {
                if (p == t)
                    return lim;
                vis[p] = 1;
                int ret = 0;
                for (int i = bus[p]; i != -1; i = e[i].next)
                {
                    int q = e[i].p;
                    if (e[i].c > 0 && dist[q] == dist[p] + e[i].w && vis[q] == 0)
                    {
                        int res = dinic_dfs(q, min(lim, e[i].c));
                        cost += res * e[i].w;
                        e[i].c -= res;
                        e[i ^ 1].c += res;
                        ret += res;
                        lim -= res;
                        if (lim == 0)
                            break;
                    }
                }
                return ret;
            }
    
            pair<int, int> solve(int _s, int _t)
            {
                s = _s;
                t = _t;
                ans = 0;
                cost = 0;
                while (dinic_spfa())
                {
                    fill(vis, vis + N, 0);
                    ans += dinic_dfs(s, inf);
                }
                return make_pair(ans, cost);
            }
        };
    } // namespace flowsolution
    
    #endif
    
    signed main()
    {
        ios::sync_with_stdio(false);
    
        int n, m;
        cin >> n >> m;
    
        int NODE_IN = 0;
        int NODE_OUT = n;
        int S = 2 * n + 1;
        int T = 2 * n + 2;
        int target = 0;
        int target_s = 0;
        flowsolution::MaxflowSolution flow;
    
        map<int, int> mp_stay;
    
        for (int i = 1; i <= n; i++)
        {
            int in_flow;
            cin >> in_flow;
            target_s += in_flow;
            flow.make(S, NODE_IN + i, in_flow);
        }
        for (int i = 1; i <= n; i++)
        {
            int out_flow;
            cin >> out_flow;
            mp_stay[i] = flow.make(NODE_IN + i, NODE_OUT + i, 1e12);
            flow.make(NODE_OUT + i, T, out_flow);
            target += out_flow;
        }
    
        map<pair<int, int>, int> mp;
    
        for (int i = 1; i <= m; i++)
        {
            int u, v;
            cin >> u >> v;
            mp[{u, v}] = flow.make(NODE_IN + u, NODE_OUT + v, 1e12);
            mp[{v, u}] = flow.make(NODE_IN + v, NODE_OUT + u, 1e12);
        }
    
        int ans = flow.solve(S, T);
        if (target == ans && target_s == ans)
        {
            cout << "YES" << endl;
            for (int i = 1; i <= n; i++)
            {
                for (int j = 1; j <= n; j++)
                {
                    if (i == j)
                        cout << flow.get_value(mp_stay[i] ^ 1) << " ";
                    else if (mp[{i, j}])
                        cout << flow.get_value(mp[{i, j}] ^ 1) << " ";
                    else
                        cout << "0 ";
                }
                cout << endl;
            }
        }
        else
        {
            cout << "NO" << endl;
        }
    }
    
  • 相关阅读:
    HDU 1982 Kaitou Kid The Phantom Thief (1)
    HDU 1984 Mispelling4
    HDU 2546 饭卡
    HDU 1009 FatMouse' Trade
    在VC 中如何隐藏一个主程序窗口
    .菜单项
    SetClassLong,GetClassLong 动态改变光标
    .窗口捕获鼠标
    .主窗口向子控件发送消息
    线段树 1698 Just a Hook 区间set更新
  • 原文地址:https://www.cnblogs.com/mollnn/p/14355883.html
Copyright © 2011-2022 走看看