第五次作业

#列表+循环 实现，并包装成一个函数
def pySum(n):
    a = list(range(10))
    b = list(range(0,5*n,5))
    c = []
    for i in range(len(b)):
        c.append(a[i]+b[i])
    return (c)

print(pySum(10))

运行结果：

import numpy
def arySum(n):
    a = numpy.arange(n)
    b = numpy.arange(0,2*n,2)
    c = a+b
    return (c)

print(arySum(10))

运行结果：

#列表实现数组相加的效率
from datetime import datetime
s_sum = datetime.now()
pySum(1000000)
delta_sum = datetime.now()-s_sum
print(delta_sum)
#实现数组相加的效率numpy
s_numpy = datetime.now()
arySum(1000000)
delta_numpy = datetime.now()-s_numpy
print(delta_numpy)

运行结果：