将php数组传递到js—json_encode()，json_decode()

json_decode()，对一个json字符串进行解码，json_encode()是生成一个json字符串

上面的解释很清楚了，关于php里数组赋值的问题，列举如下：

<?php

//对象
class JsonTest{
var $id = 1;
var $name = 'heiyeluren';
var $gender = '男';
}
$obj = new JsonTest;
echo json_encode($obj)."<br />";  //{"id":1,"name":"heiyeluren","gender":"u7537"}

//数字索引数组
$arr1 = array(1, 'heiyeluren', '男');
echo json_encode($arr1)."<br />";  //[1,"heiyeluren","u7537"]

//关联索引数组
$arr2 = array("id"=>1,"name"=>'heiyeluren',"gender"=>'男');
echo json_encode($arr2)."<br />";  //{"id":1,"name":"heiyeluren","gender":"u7537"}

//多维数字索引数组
$arr3 = array(array(1, 'heiyeluren', '男'), array(1, 'heiyeluren', '男'));
echo json_encode($arr3)."<br />";  //[[1,"heiyeluren","u7537"],[1,"heiyeluren","u7537"]]

//关联索引数组
$arr4 = array(array("id"=>1,"name"=>'heiyeluren',"gender"=>'男'), array("id"=>1,"name"=>'heiyeluren',"gender"=>'男'));
echo json_encode($arr4)."<br />";  
//[{"id":1,"name":"heiyeluren","gender":"u7537"},{"id":1,"name":"heiyeluren","gender":"u7537"}]
?>

*（备注：关于在JS里调用传过来的数组的问题。可以用object的方式：obj.id、obj.name但是更多时候，它显示给我undefined，所以更推荐大家用数组的方式：obj[id]、obj[name] ）