Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
, return true.
Given "foo"
, "bar"
, return false.
Given "paper"
, "title"
, return true.
判断2个字符串是否同构,思路:可先将字符串转换成abc的形式,若同构则转换后的字符串应该相等,代码如下:
public class Solution { /** * 将字符串转换成abc的形式如egg->abb,paper->abacd */ public String transform(String s) { StringBuffer re = new StringBuffer(""); char tmp = 'a'; Map<Character,Character> map = new HashMap<Character,Character>(); for(int i=0;i<s.length();i++) { if(!map.containsKey(s.charAt(i))) { map.put(s.charAt(i),tmp); re.append(tmp); tmp++; } else { re.append(map.get(s.charAt(i))); } } return re.toString(); } public boolean isIsomorphic(String s, String t) { if(transform(s).equals(transform(t))) return true; else return false; } }