Sql server 删除重复记录的SQL语句 枫

有两个意义上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复，比较容易解决，使用
select distinct * from tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。

2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下
假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写在select子句中省去此列）

3、部分关键字段重复，且记录中有ID.

第一种方法可一次删除所有重复的..(只保留重复中ID最小的记录)。
delete from table where id not in ( select min(id) from table group by name)

第二种方法每次只删除重复中ID最大的一条记录。

delete from table where id in ( select max(id) from table group by name having count(*)>1)

4、SQL程序删除

declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) > 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0

自己还得出的办法：
select   *   from   user1     where   [id]   not   in   (select   top   1   [id]   from   user1   a   where   name=user1.name)  
  --删就这样写  
  delete   from   user1     where   [id]   not   in   (select   top   1   [id]   from   user1   a   where   name=user1.name)
或 delete from user where id not in ( select max(id) from user where name=user.name)
delete [user] where id not in (select max(id) from [user] group by name having count(*) > 1)
max 或 min看具体情况而论。

其他方法：
----A:保留id最大的行,删除其它行  
  --方法1  
  delete   [user]   from   [user]   t    
  inner   join(select   name,max(id)   as   id   from   [user]   group   by   name)   a  
  on   t.name   =   a.name   and   t.id   <>   a.id  
  --方法2  
  delete   [user]   from   [user]   t  
  where     exists(select   *   from   [user]   where   name   =   t.name   and   id   >   t.id)  
   
  ----B:保留id最小的行,删除其它行  
  --方法1  
  delete   [user]   from   [user]   t    
  inner   join(select   name,min(id)   as   id   from   [user]   group   by   name)   a  
  on   t.name   =   a.name   and   t.id   <>   a.id  
  --方法2  
  delete   [user]   from   [user]   t  
  where     exists(select   *   from   [user]   where   name   =   t.name   and   id   <   t.id)  
   
  ----C:删除所有重复的name行,一行也不留  
  delete   [user]   from   [user]   t    
  inner   join    
  (select   id   from   [user]   a   where   exists(select   *   from   [user]   where   name   =   a.name   group   by   name   having   count(*)   >   1))   as   b  
  on   t.id   =   b.id