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  • 关于json解析的几种方法

    parse用于从一个字符串中解析出json对象,如 

    var str = '{"name":"huangxiaojian","age":"23"}'

    注意:单引号写在{}外,每个属性名都必须用双引号,否则会抛出异常。

    JSON.parse(jsonString): 在一个字符串中解析出JSON对象

    var str = '[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]';
      
    JSON.parse(str);
     结果

    /*---------------------------------------------------------------------------------*/

    2、JSON.stringify(obj) : 将一个JSON对象转换成字符串

    var obj = [{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}];
      
    JSON.stringify(obj);
     
    结果
    "[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]"

    /*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/

    3、jQuery.parseJSON(jsonString) : 将格式完好的JSON字符串转为与之对应的JavaScript对象

    var str = '[{"href":"baidu.com","text":"test","orgId":123,"dataType":"curry","activeClass":"haha"}]';
      
    jQuery.parseJSON(str);
    结果

    /*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/

    4、JSON.parse()和jQuery.parseJSON()的区别:

    有的浏览器不支持JSON.parse()方法,使用jQuery.parseJSON()方法时,在浏览器支持时会返回执行JSON.parse()方法的结果,否则会返回类似执行eval()方法的结果,以上结论参考jquery 1.9.1 得出:

    parseJSON: function( data ) {
      // Attempt to parse using the native JSON parser first
      if ( window.JSON && window.JSON.parse ) {
        return window.JSON.parse( data );
      }
      
      
      if ( data === null ) {
        return data;
      }
      
      
      if ( typeof data === "string" ) {
      
      
        // Make sure leading/trailing whitespace is removed (IE can't handle it)
        data = jQuery.trim( data );
      
      
        if ( data ) {
          // Make sure the incoming data is actual JSON
          // Logic borrowed from http://json.org/json2.js
          if ( rvalidchars.test( data.replace( rvalidescape, "@" )
            .replace( rvalidtokens, "]" )
            .replace( rvalidbraces, "")) ) {
      
      
            return ( new Function( "return " + data ) )();
          }
        }
      }
      
      
      jQuery.error( "Invalid JSON: " + data );
    },

    /*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/

    /*---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------*/

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  • 原文地址:https://www.cnblogs.com/msb-/p/6485290.html
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