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  • Big Number

    Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)

    Total Submission(s) : 34   Accepted Submission(s) : 24
    Problem Description
    As we know, Big Number is always troublesome. But it's really important in our ACM. And today, your task is to write a program to calculate A mod B. To make the problem easier, I promise that B will be smaller than 100000. Is it too hard? No, I work it out in 10 minutes, and my program contains less than 25 lines.
     
    Input
    The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000, and B will be smaller than 100000. Process to the end of file.
     
    Output
    For each test case, you have to ouput the result of A mod B.
     
    Sample Input
    2 3 12 7 152455856554521 3250
     

    Sample Output
    2 5 1521
     


    
    
    
    
    
    
    
    
    
    
    #include<stdio.h>
    #include<string.h>
    char x[1000000];
    int main()
    {
        int n,i,j,k,a,b,c;
        while(scanf("%s%d",x,&n)!=EOF)
        {
           a=0;
           for(i=0;i<strlen(x);i++)
           {
             a=a*10+x[i]-'0';
             a=a%n;    
           }
           printf("%d
    ",a);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/mthoutai/p/7210518.html
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