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  • 二叉搜索树(python)

    # -*- coding: utf-8 -*-
    
    
    class BSTNode(object):
        def __init__(self, key, value, left=None, right=None):
            self.key, self.value, self.left, self.right = key, value, left, right
    
    
    class BST(object):
        def __init__(self, root=None):
            self.root = root
    
        @classmethod
        def build_from(cls, node_list):
            cls.size = 0
            key_to_node_dict = {}
            for node_dict in node_list:
                key = node_dict['key']
                key_to_node_dict[key] = BSTNode(key, value=key)  
    
            for node_dict in node_list:
                key = node_dict['key']
                node = key_to_node_dict[key]
                if node_dict['is_root']:
                    root = node
                node.left = key_to_node_dict.get(node_dict['left'])
                node.right = key_to_node_dict.get(node_dict['right'])
                cls.size += 1
            return cls(root)
    
        def _bst_search(self, subtree, key):
            if subtree is None:   # 没找到
                return None
            elif key < subtree.key:
                return self._bst_search(subtree.left, key)
            elif key > subtree.key:
                return self._bst_search(subtree.right, key)
            else:
                return subtree
    
        def __contains__(self, key):
            """实现 in 操作符"""
            return self._bst_search(self.root, key) is not None
    
        def get(self, key, default=None):
            node = self._bst_search(self.root, key)
            if node is None:
                return default
            else:
                return node.value
    
        def _bst_min_node(self, subtree):
            if subtree is None:
                return None
            elif subtree.left is None:   # 找到左子树的头
                return subtree
            else:
                return self._bst_min_node(subtree.left)
    
        def bst_min(self):
            node = self._bst_min_node(self.root)
            return node.value if node else None
    
        def _bst_insert(self, subtree, key, value):
            """ 插入并且返回根节点
    
            :param subtree:
            :param key:
            :param value:
            """
            if subtree is None:   # 插入的节点一定是根节点,包括 root 为空的情况
                subtree = BSTNode(key, value)
            elif key < subtree.key:
                subtree.left = self._bst_insert(subtree.left, key, value)
            elif key > subtree.key:
                subtree.right = self._bst_insert(subtree.right, key, value)
            return subtree
    
        def add(self, key, value):
            node = self._bst_search(self.root, key)
            if node is not None:   # 更新已经存在的 key
                node.value = value
                return False
            else:
                self.root = self._bst_insert(self.root, key, value)
                self.size += 1
                return True
    
        def _bst_remove(self, subtree, key):
            """删除节点并返回根节点"""
            if subtree is None:
                return None
            elif key < subtree.key:
                subtree.left = self._bst_remove(subtree.left, key)
                return subtree
            elif key > subtree.key:
                subtree.right = self._bst_remove(subtree.right, key)
                return subtree
            else:  
                if subtree.left is None and subtree.right is None:    
                    return None
                elif subtree.left is None or subtree.right is None:  
                    if subtree.left is not None:
                        return subtree.left   
                    else:
                        return subtree.right
                else:  
                    successor_node = self._bst_min_node(subtree.right)
                    subtree.key, subtree.value = successor_node.key, successor_node.value
                    subtree.right = self._bst_remove(subtree.right, successor_node.key)
                    return subtree
    
        def remove(self, key):
            assert key in self
            self.size -= 1
            return self._bst_remove(self.root, key)
    
    
    NODE_LIST = [
        {'key': 60, 'left': 12, 'right': 90, 'is_root': True},
        {'key': 12, 'left': 4, 'right': 41, 'is_root': False},
        {'key': 4, 'left': 1, 'right': None, 'is_root': False},
        {'key': 1, 'left': None, 'right': None, 'is_root': False},
        {'key': 41, 'left': 29, 'right': None, 'is_root': False},
        {'key': 29, 'left': 23, 'right': 37, 'is_root': False},
        {'key': 23, 'left': None, 'right': None, 'is_root': False},
        {'key': 37, 'left': None, 'right': None, 'is_root': False},
        {'key': 90, 'left': 71, 'right': 100, 'is_root': False},
        {'key': 71, 'left': None, 'right': 84, 'is_root': False},
        {'key': 100, 'left': None, 'right': None, 'is_root': False},
        {'key': 84, 'left': None, 'right': None, 'is_root': False},
    ]
    
    
    def test_bst_tree():
        bst = BST.build_from(NODE_LIST)
        for node_dict in NODE_LIST:
            key = node_dict['key']
            assert bst.get(key) == key
        assert bst.size == len(NODE_LIST)
        assert bst.get(-1) is None    
    
        assert bst.bst_min() == 1
    
        bst.add(0, 0)
        assert bst.bst_min() == 0
    
        bst.remove(12)
        assert bst.get(12) is None
    
        bst.remove(1)
        assert bst.get(1) is None
    
        bst.remove(29)
        assert bst.get(29) is None
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  • 原文地址:https://www.cnblogs.com/muzinan110/p/11167102.html
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