用requests库爬取猫眼电影Top100

这里需要注意一下，在爬取猫眼电影Top100时，网站设置了反爬虫机制，因此需要在requests库的get方法中添加headers，伪装成浏览器进行爬取

import requests
from requests.exceptions import RequestException
from multiprocessing import Pool
import re
import json

def get_one_page(url):
    try:
        headers = {"User-Agent": "Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36"}
        response = requests.get(url, headers=headers)
        if response.status_code == 200:
            return response.text
    except RequestException:
        return None

def parse_one_page(html):
    pattern = re.compile('<dd>.*?board-index.*?>(d+)</i>.*?data-src="(.*?)".*?name"><a'
                         +'.*?>(.*?)</a>.*?star">(.*?)</p>.*?releasetime">(.*?)</p>'
                         +'.*?integer">(.*?)</i>.*?fraction">(.*?)</i>.*?</dd>', re.S)
    items = re.findall(pattern, html)
    for item in items:
        yield {
            'index': item[0],
            'image': item[1],
            'title': item[2],
            'actor': item[3].strip()[3:],
            'time': item[4].strip()[5:],
            'score': item[5] + item[6]
        }

def write_to_file(content):
    with open('result.txt', 'a', encoding='utf-8') as f:
        f.write(json.dumps(content, ensure_ascii=False) + '
')
        f.close()

def main(offset):
    url = "http://maoyan.com/board/4?offset=" + str(offset)
    html = get_one_page(url)
    for item in parse_one_page(html):
        print(item)
        write_to_file(item)


if __name__ == '__main__':
    pool = Pool()
    pool.map(main, [i*10 for i in range(10)])

运行结果如下：