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  • 【HDOJ6324】Grab The Tree(博弈)

    题意:

    思路:

     1 #include <stdio.h>
     2 #include <vector>
     3 #include <algorithm>
     4 #include <string.h>
     5 #include <limits.h>
     6 #include <string>
     7 #include <iostream>
     8 #include <queue>
     9 #include <math.h>
    10 #include <stack>
    11 #include <map>
    12 #define left (now<<1)
    13 #define right ((now<<1)+1)
    14 #define mid ((l+r)>>1)
    15 using namespace std;
    16 typedef long long int lint;
    17 
    18 const int MAXN = 1e5 + 10;
    19 
    20 int t,n,m;
    21 int p[40];
    22 
    23 void chai(int num){
    24     for(int i = 0; i <= 31; ++i){
    25         int k = num & 1;
    26         num = num >> 1;
    27         if(k == 1){ p[i]++;}
    28     }
    29 }
    30 
    31 int main(){
    32     scanf("%d",&t);
    33     while(t--){
    34         scanf("%d",&n); memset(p,0,sizeof(p));
    35         for(int i = 1; i <= n; ++i){
    36             int num; scanf("%d",&num); chai(num);
    37         }
    38         for(int i = 1; i < n; ++i){
    39             int u,v; scanf("%d%d",&u,&v);
    40         }
    41         int can = -1;;
    42         for(int i = 31; i >= 0; --i){
    43             if(p[i] % 2 == 1){
    44                 can = 1; break;
    45             }
    46         }
    47 //        for(int i = 0; i <= 4; ++i){
    48 //            printf("%d ",p[i]);
    49 //        }
    50         if(can == -1){
    51             printf("D
    ");
    52         }else{
    53             printf("Q
    ");
    54         }
    55     }
    56     return 0;
    57 }
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  • 原文地址:https://www.cnblogs.com/myx12345/p/9405771.html
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