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  • P4178 Tree

    最简单的点分治

    淀粉质的思想:

    “分而治之”,缩小问题规模,合并求解;

      1 #include<cstdio>
      2 #include<cmath>
      3 #include<cstring>
      4 #include<algorithm>
      5 #include<iostream>
      6 using namespace std;
      7 #define up(i,l,r) for(register int i = (l); i <= (r); ++i)
      8 #define dn(i,l,r) for(register int i = (l); i >= (r); --i)
      9 #define ll long long
     10 #define re register
     11 using namespace std;
     12 
     13 template <typename T> void in(T &x) {
     14     x = 0; T f = 1; char ch = getchar();
     15     while(!isdigit(ch)) {if(ch == '-') f = -1; ch = getchar();}
     16     while( isdigit(ch)) {x = 10 * x + ch - 48; ch = getchar();}
     17     x *= f;
     18 }
     19 
     20 template <typename T> void out(T x) {
     21     if(x < 0) x = -x , putchar('-');
     22     if(x > 9) out(x/10);
     23     putchar(x%10 + 48);
     24 }
     25 //---------------------------------------------------------
     26 
     27 const int N = 40007;
     28 
     29 struct edge {
     30     int v,w,nxt;
     31 } e[N<<1];int tot,head[N];
     32 
     33 void add(int u,int v,int w) {
     34     e[++tot].v = v;
     35     e[tot].w = w;
     36     e[tot].nxt = head[u];
     37     head[u] = tot;
     38 }
     39 //---------------------------------------------------------
     40 
     41 int n,k,ans;
     42 int size[N];
     43 int Tsize,cnt,rt;
     44 int cdis[N],dis[N];
     45 bool vis[N];
     46 
     47 int f[N];
     48 void get_rt(int u,int fa) {
     49     size[u] = 1; f[u] = 0;
     50     for(re int i = head[u]; i; i = e[i].nxt) {
     51         int v = e[i].v; if(v == fa || vis[v]) continue;
     52         get_rt(v,u);
     53         size[u] += size[v];
     54         f[u] = max(size[v],f[u]);
     55     }
     56     f[u] = max(f[u],Tsize-size[u]);
     57     if(f[u] < f[rt]) rt = u;
     58 }
     59 
     60 void get_dis(int u,int fa) {
     61     cdis[++cnt] = dis[u];
     62     for(re int i = head[u]; i; i = e[i].nxt) {
     63         int v = e[i].v; if(v == fa || vis[v]) continue;
     64         dis[v] = dis[u] + e[i].w; get_dis(v,u);
     65     }
     66 }
     67 
     68 int calc(int u) {
     69     cnt = 0,get_dis(u,0);
     70     sort(cdis+1,cdis+cnt+1);
     71     int l = 1,r = cnt,sum = 0;
     72     while(l < r) {
     73         if(cdis[l] + cdis[r] <= k) sum += r-l,++l;
     74         else --r; 
     75     }
     76     return sum;
     77 }
     78 
     79 void new_tree(int u) {
     80     vis[u] = 1; dis[u] = 0;//
     81     ans += calc(u);
     82     for(re int i = head[u]; i; i = e[i].nxt) {
     83         int v = e[i].v; if(vis[v]) continue;
     84         dis[v] = e[i].w;//
     85         ans -= calc(v);
     86         rt = 0,Tsize = size[v];
     87         get_rt(v,0); new_tree(rt);
     88     }
     89 } 
     90 
     91 
     92 void init() {
     93     memset(head,0,sizeof(head));
     94     memset(vis,0,sizeof(vis));
     95     Tsize = n,rt = 0,f[0] = n+1; ans = 0;
     96 }
     97 
     98 int main() {
     99     freopen("input.txt","r",stdin);
    100     in(n);
    101     init(); int x,y,w;
    102     up(i,1,n-1) in(x),in(y),in(w),add(x,y,w),add(y,x,w);in(k);
    103     get_rt(1,0); new_tree(rt);
    104     out(ans); putchar('
    ');
    105 }
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  • 原文地址:https://www.cnblogs.com/mzg1805/p/10737145.html
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