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  • CF 22B. Bargaining Table

    水题。好久没有写过优化搜索题了。

     1 #include <cstdio>
     2 #include <cstring>
     3 #include <iostream>
     4 #include <vector>
     5 using namespace std;
     6 char str[31][31];
     7 int r[31][31];
     8 int c[31][31];
     9 int judge(int rx,int ry,int lx,int ly)
    10 {
    11     int i,j;
    12     for(i = lx;i <= rx;i ++)
    13     {
    14         for(j = ly;j <= ry;j ++)
    15         {
    16             if(str[i-1][j-1] == '1')
    17             return 0;
    18         }
    19     }
    20     return 1;
    21 }
    22 int main()
    23 {
    24     int n,m,i,j,k,u,ans;
    25     scanf("%d%d",&n,&m);
    26     for(i = 0;i < n;i ++)
    27     scanf("%s",str[i]);
    28     ans = 0;
    29     for(i = 1;i <= n;i ++)
    30     {
    31         for(j = 1;j <= m;j ++)
    32         {
    33            if(str[i-1][j-1] == '0')
    34            {
    35                r[i][j] = r[i-1][j] + 1;
    36                c[i][j] = c[i][j-1] + 1;
    37            }
    38            else
    39            {
    40                r[i][j] = 0;
    41                c[i][j] = 0;
    42            }
    43         }
    44     }
    45     for(i = n;i >= 1;i --)
    46     {
    47         for(j = m;j >= 1;j --)
    48         {
    49             for(k = 1;k <= r[i][j];k ++)
    50             {
    51                 for(u = 1;u <= c[i][j];u ++)
    52                 {
    53                     if(ans >= (k+u)*2) continue;
    54                     if(judge(i,j,i-k+1,j-u+1))
    55                     {
    56                         ans = max(ans,(k+u)*2);
    57                     }
    58                 }
    59             }
    60         }
    61     }
    62     printf("%d
    ",ans);
    63     return 0;
    64 }
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  • 原文地址:https://www.cnblogs.com/naix-x/p/3397309.html
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